Question

What is the slope of the secant line? Thank you

Answer 1

Answer:

Given that,

The function is,

$f(x)=1.2x^3-37x^2+265x+555$

To find: To find the slope of the secant line from x1=0 and x2=4

Explanation:

First we find the corresponding y values that is y1 and y2 for the given x1 and x2 respectively.

we get,

Whwn x1=0,

$y1=f(x1)=f(0)$

$f(0)=1.2(0)^3-37(0)^2+265(0)+555$$f(0)=555$$y1=555$

When x2=4, we get,

$f(4)=1.2(4)^3-37(4)^2+265(4)+555$$f(4)=1099.8$

To find the slope of the line passing the points (0,555), (4,1099.8)

we know that,

Slope of the line passing through the points (x1,y1) and (x2,y2)

$m=\frac{y2-y1}{x2-x1}$

we get,

$m=\frac{1099.8-555}{4-0}$$m=\frac{544.8}{4}$$m=136.2$

Answer is:

Slope of the secant line from x1=0 and x2=4 is 136.2.