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igor_vitrenko [27]
3 years ago
10

A group of 121 Internet users 50-65 years of age were randomly chosen and asked to report the weekly number of hours they spend

online. The purpose of the study was to determine whether the mean weekly number of hours that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours. A 95% confidence interval for the mean weekly number of hours that Internet users in that age group spend online was calculated to be (11.439 , 12.577). On the basis of this interval, at α = 0.05, what can she conclude about H0: μ = 12.50 versus Ha: μ ≠ 12.50?
Mathematics
1 answer:
Luda [366]3 years ago
7 0

Answer: We support the null hypothesis.

Step-by-step explanation:

Given : The purpose of the study was to determine whether the mean weekly number of hours that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.

The set of hypothesis for the given claim :-

H_0:\mu=12.50\\\\ H_a:\mu\neq12.50

A 95% confidence interval for the mean weekly number of hours that Internet users in that age group spend online was calculated to be (11.439 , 12.577).

Since 12.50 contained in the 95% confidence interval (11.439 , 12.577).

Therefore, we support the null hypothesis.

So the final conclusion will be, we have evidence to support the claim that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.

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PLEASE HELP<br><br> Graph the ordered pairs for y = 3x + 3 using r = {-2, 1, 2}.
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Answer:

  (-2, -3), (1, 6), (2, 9) are plotted in the attached graph

Step-by-step explanation:

For x = -2, y = 3(-2) +3 = -3. The ordered pair is (-2, -3).

For x = 1, y = 3(1) +3 = 6. The ordered pair is (1, 6).

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The graph is attached.

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2 years ago
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What is the value of a?
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Answer:

a = 62

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

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7 0
3 years ago
I need help n explainnnn please ​
kobusy [5.1K]

The Correct option is D). y=1x+1 And y=2x+2

Step-by-step explanation:

The equation of a line is given as y=mx+c.

where m=slope of line and c=y intercept

The slope of line is given as  m=\frac{(Y2-Y1)}{(X2-X1)}

Solving for Redline:

From the given graph, redline passes through (-1,0) and (0,1)

The slope of Redline is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Redline is  m=\frac{(1-0)}{(0-(-1))}

The slope of Redline is  m=(1)

And Y-intercept is 1

The equation of a Redline is given as y=1x+1

Solving for Blue-line:

From the given graph, Blue-line passes through (-1,0) and (0,2)

The slope of Blue-line is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Blue-line is  m=\frac{(2-0)}{(0-(-1))}

The slope of Blue-line is  m=(2)

And Y-intercept is 2

The equation of a Blue-line is given as y=2x+2

The Correct option is D). y=1x+1 And y=2x+2

7 0
2 years ago
Answers to page 691-693 #1-30
nadezda [96]
What book do you need these answers from?
8 0
3 years ago
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