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3 years ago

2/3-1/6=? Pls help I suck at fractions

Mathematics

2 answers:

Andru [333]3 years ago

5 0

Answer:

1/2

Step-by-step explanation:

so 2/3 you want it as a common fraction so 3*2=6

then yo do it for the top 2*2=4

4/6-1/6=3/6

3/6=1/2

hope this helps

Stells [14]3 years ago

4 0

Answer:

1/2

Step-by-step explanation:

2/3 - 1/6 = 4-1/6 = 3/6, Cancel the common factor 3 and you get 1/2.

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vichka [17]

0.65 x 40 = 26
So the answer is 26 pounds.

7 0

2 years ago

Read 2 more answers

For a walk-a-thon a sponsor committed to give you a flat free of $5 plus $2 for every mile m you walk

Iteru [2.4K]

Answer:

$45

Step-by-step explanation:

THIS IS THE COMPLETE QUESTION BELOW;

For a walk-a-thon a sponsor committed to give you a flat fee of $5 plus $2 for every mile you walk. If you walk for 20 miles, what is the total amount you will collect from your sponsor at the end of the walk-a-thon?

$5 was given for participants of the walk-a-thon.

$2 was given for every miles won

Then, for "y" number of miles, the the amount that can be won is ( 2×y)= 2y

The Total amount that can be given

= (5 + 2y)

Where "y" is the miles value

Then, if you walk for 20 miles, The Total amount that can be given

= 5 + 2(20)

= 5+ 40

= $45

3 0

2 years ago

8x + 11 = 2(4x - 7) + 25<br> Step by step please!

Dimas [21]

Step-by-step explanation:

8x + 11=2(4x-7) + 25

8x + 11 = 8x - 14 + 25

8x + 11=8x- 14 + 14 +25 + 11

8x-8x + 11 -11 = 14 + 25 + 11

8x-8x =14 + 25 + 11

X = 50

3 0

2 years ago

What is the equation to the expression -2-3(-4)?

RoseWind [281]

Answer:

c) -1

Step-by-step explanation:

-2-3-(-4)

=-5+4

=-1

8 0

2 years ago

An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the

julia-pushkina [17]

Answer:

The rate of decrease is: $43.2mm^3/min$

Step-by-step explanation:

Given

$l = 18mm$

$\frac{dl}{dt} = -0.8mm/min$ ---- We used minus because the rate is decreasing

Required

Rate of decrease when: $l = 18mm$

The volume of the cube is:

$V = l^3$

Differentiate

$\frac{dV}{dl} = 3l^2$

Make dV the subject

$dV = 3l^2 \cdot dl$

Divide both sides by dt

$\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}$

Given that: $l = 18mm$ and $\frac{dl}{dt} = -0.8mm/min$

$\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)$

$\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min$

$\frac{dV}{dt} = -43.2mm^3/min$

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

8 0

2 years ago