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IRINA_888 [86]
2 years ago
7

3m-2-5n+p terms and coefficients

Mathematics
1 answer:
Firlakuza [10]2 years ago
4 0

Answer: Answers are in the steps.

Step-by-step explanation:

The coefficients are 3, -5, and 1  

The terms are, 3m, -2,-5n and p

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WILL MARK BRAINLIST PLS HELP:))
dusya [7]

Answer:

Vertex: (3,0)

Max/min: min

axis of symmetry: x=3

Domain: (-∞,∞)

Range: [3,∞)

zeroes: (3,0)

Step-by-step explanation:

Vertex is where the graph changes directions (so in this case it's the point where it changes from decreasing to increasing) which I think is (3,0)

It's a minimum because the coefficent for the degree is positive

The axis of symmetry is just the x value of the vertex (which is x= 3)

the domain is all possible x values (-∞,∞)

The range is all possible y values [3,∞)

The zeroes is where the line hits the x axis, which is (3,0)

6 0
3 years ago
What is the slope of the line shown below?
zhannawk [14.2K]

Answer:

The slope of the line is -3.

Step-by-step explanation:

The slope equation is:

m= y2-y1/x2-x1

In this case:

m= -3-6/2+1     (remember that a negative minus a negative gives you a positive)

Which equals:

m=-9/3

Divide and you get -3.

5 0
3 years ago
Hey!!! What is −6+(−12)
SSSSS [86.1K]

Answer:

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Step-by-step explanation:

Essentially the same as (-6) - 12

7 0
3 years ago
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How do you do inequalities
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So some quick tips for inequalities:
**What you do to one side you HAVE TO do it to the other 2**
**If you ever divide a negative number past the inequality signs, the signs FLIP!!**
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I hope that this has helped!
8 0
2 years ago
Is this an example of a horizontal asymptote?
8_murik_8 [283]

Answer:

Step-by-step explanation:

Hi there,

The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.

To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.

With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.

Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!

thanks,

6 0
3 years ago
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