The coordinates of vertex B' is 
.
<h3>
How to calculate the coordinate of point by reflection</h3>
A point if reflected across the line 
by means of the following formula:
![P'(x,y) = P(x,y)+2\cdot [(x_{P}, -2)-P(x,y)]](https://tex.z-dn.net/?f=P%27%28x%2Cy%29%20%3D%20P%28x%2Cy%29%2B2%5Ccdot%20%5B%28x_%7BP%7D%2C%20-2%29-P%28x%2Cy%29%5D)
(1)
Where:
- Original point
- x-Coordinate of point P
- Resulting point
If we know that 
and 
, then the coordinates of the vertex is:
![P'(x,y) = (-2, 4) + 2\cdot [(-2,-2)-(-2,4)]](https://tex.z-dn.net/?f=P%27%28x%2Cy%29%20%3D%20%28-2%2C%204%29%20%2B%202%5Ccdot%20%5B%28-2%2C-2%29-%28-2%2C4%29%5D)
The coordinates of vertex B' is . 
To learn more on reflections, we kindly invite to check this verified question: brainly.com/question/1878272
Answer: x = 4
Step-by-step explanation: f(2) = 3(2)-1 = 5. Meaning x needs to be a value that makes g(x) = 5. You can set them up equal to each other 5 = 2x-3 and solve. You end up getting x = 4.
Answer:
<em>− 2sin(b) / cos(2b)</em>
Step-by-step explanation:
DIFFERENTIATE W.R.T. B is a different method entirely
We simply add together the numerators and set with 2cos
then keep this number and add to sinb and square it.
then repeat initial 2 + cosb ^2 but instead of multiplying its add.
Then set the whole division to -sin (2b) squared then +1
<em> − 2cos(b)(3(sin(b))^2+(cos(b))^2) / −(sin(2b)) ^2 +1 </em>
<span>"How many rectangles can u make with 20 cubes"
The answer is 4</span>
