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3 years ago

Multiply 6x^2-4x-5(2x^2+3x)

Mathematics

2 answers:

vampirchik [111]3 years ago

4 0

Answer:

$\large\boxed{6x^2-4x-5(2x^2+3x)=-4x^2-19x}$

Step-by-step explanation:

$6x^2-4x-5(2x^2+3x)\qquad\text{use the distributive property}\\\\=6x^2-4x+(-5)(2x^2)+(-5)(3x)\\\\=6x^2-4x-10x^2-15x\qquad\text{combine like terms}\\\\=(6x^2-10x^2)+(-4x-15x)\\\\=-4x^2-19x$

Anna35 [415]3 years ago

4 0

Answer:

Step-by-step explanation:

I learned to solve these with a box method.

6x^2 -4x -5

2x^2

with this method you add the matching terms

6x^2 -4x -5

2x^2 | 1 | 2 | 3

3x | 2 | 3 | 4

6x^2 -4x -5

2x^2 | 12x^4 | -8x^3 | -10x^2

3x | 18x^3 | -12x^2 | -15x

12x^4 + 10x^3 - 22x^2 - 15x

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$\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}$

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1 year ago

F(x)= x^2 -16x+63 find the x-intercepts of this function

Ahat [919]

Answer:

The x-intercepts will be, x= 7 or x =9

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f(x)= x^2 -16x+63

At the x-intercept, f(x) is zero.

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product = 63

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x = 7 or x = 9

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The x-intercepts will be, x= 7 or x =9

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