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son4ous [18]
2 years ago
12

Please solve I need help!

Mathematics
1 answer:
ladessa [460]2 years ago
5 0
24 is the answer welcome !
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A triangle has an area of 600 square feet. The height of the triangle is 20 feet. The base of the triangle is
sdas [7]

Answer: 60

Step-by-step explanation:

Area = ½base × height

600 = ½b × 20

600/20 = ½b

Base = 30 × 2

7 0
2 years ago
How many times larger is 2⁴⁵ than 2⁴²​
andre [41]

Answer:

hi

Step-by-step explanation:

2⁴⁵÷2⁴²=2³

2³=8

hope it helps

have a nice day

7 0
3 years ago
Read 2 more answers
Some angles are shown. Complete each of the 2 activities for this Task. Activity 1 of 2 The measure of angle NOP is 140°. Which
garik1379 [7]

Answer:

A. 23+x=140

Step-by-step explanation:

The angle addition postulate states that the measure of a larger angle formed by two or more smaller angles placed side by side is the the sum of the smaller angles. The angle addition postulate states that if B is in the interior of AOC , then:

m∠AOB + m∠BOC = m∠AOC.

From the image:

∠NOP = ∠NOQ + ∠QOP

∠NOP = 140, ∠NOQ = x, ∠QOP = 23

substituting:

140 = x + 23

x = 140 - 23 = 117

∠NOQ = 117°

6 0
3 years ago
Look at picture. What is the solution WORTH 10 points. Show work.
lakkis [162]

\left\{\begin{array}{ccc}2x-y=6\\2x-2y=4&|\text{add 2y to both sides}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\2x=4+2y&|\text{divide both sides by 2}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\x=2+y\end{array}\right\\\\\text{Substitute x=2+y to the first equation}\\\\2(2+y)-y=6\ \ \ \ |\text{use distributive property}\\(2)(2)+(2)(y)-y=6\\4+2y-y=6\\4+y=6\ \ \ \ \ |\text{subtract 4 from both sides}\\\boxed{y=2}\\\\\text{Put the value of y to the second equation}\\\\x=2+2\\\boxed{x=4}

Answer:\ D.\ (4,\ 2)

8 0
3 years ago
Read 2 more answers
Which equation represents the polar form of x² + (y + 4)² = 16?
Paraphin [41]

x^2+y^2=r^2\hspace{5em}x=r\cos(\theta )\hspace{5em}y=r\sin(\theta ) \\\\[-0.35em] ~\dotfill\\\\ x^2+(y+4)^2=16\implies x^2+\stackrel{binomial~expansion}{y^2+8y+16}=16 \\\\\\ \underset{x^2+y^2}{r^2} + 8(~\underset{8y}{r\sin(\theta )}~)=16-16\implies r^2+8r\sin(\theta)=0 \\\\\\ r^2=-8r\sin(\theta )\implies \cfrac{r^2}{r}=-8\sin(\theta )\implies r=-8\sin(\theta )

3 0
1 year ago
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