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3 years ago

Why hydrochloric acid neutralized first when you titrate a mixture of Hcl&ch3cooH against standard sodium hydroxide

Chemistry

1 answer:

Firdavs [7]3 years ago

3 0

Explanation:

We are given a mixture of hydrochloric acid (HCl) and acetic acid $(CH_3COOH)$ . The given mixture is a mixture of strong acid and a weak acid.

Strong acid is defined as the acid that can be get completely ionized or dissociated in an aqueous solution. Weak acid is defined as the acid which does not dissociate completely in an aqueous solution.

When a mixture of HCl and $CH_3COOH$ is titrated against NaOH (strong base), strong acid will get neutralized first because it is completely dissociated in the solution and can be easily neutralized.

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A shopkeeper has a few bottles of soft drinks in his shop.But,these are not labelled.He has to serve the drinks on the demand on

zepelin [54]

Answer:

He will decide which drink is to be served to whom, by the use of litmus paper.

Explanation:

The litmus paper is the most common indicator to determine the acidity or basicity of a solution. Blue litmus paper changes its color to red when a solution changes from basic to acidic while red litmus paper changes its color to blue when the opposite occurs (acid → basic).

First of all the litmus paper strip, pH indicator, is immersed in a solution and allowed to pass between 10 and 15 seconds while keeping the strip submerged. Afterwards it is removed, and then the strip compares the color. If the color is diffuse, there is a color scale where it is determined which solution has alkaline or acidic pH

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3 years ago

Balance the equation AlCl3 + H2SO4 yields Al2(SO4)3 +HCl

Natalija [7]

Answer:

2AlCl3 + 3H2SO4 → Al2(SO4)3 + 6HCl

Explanation:

3 0

3 years ago

If you try to balance an equation by changing subscripts you change...

aksik [14]

Answer:

kwkrofofoxosowoqoaododpdprofpcoxozoskawkdjdn

Explanation:

sklwlrlfclxoskkekrdododosoekekrkrododowoekekfkdodkwkeororkdkdkwejrjrkfidiwi3jr

8 0

3 years ago

7. The equilibrium constant Kc for the reaction H2(g) + I2(g) ⇌ 2 HI(g) is 54.3 at 430°C. At the start of the reaction there are

Juli2301 [7.4K]

Answer:

[H2] = 0.0692 M

[I2] = 0.182 M

[HI] = 0.826 M

Explanation:

Step 1: Data given

Kc = 54.3 at 430 °C

Number of moles hydrogen = 0.714 moles

Number of moles iodine = 0.984 moles

Number of moles HI = 0.886 moles

Volume = 2.40 L

Step 2: The balanced equation

H2 + I2 → 2HI

Step 3: Calculate Q

If we know Q, we know in what direction the reaction will go

Q = [HI]² / [I2][H2]

Q= [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Q =(n(HI)²) /(nH2 *nI2)

Q = 0.886²/(0.714*0.984)

Q =1.117

Q<Kc This means the reaction goes to the right (side of products)

Step 2: Calculate moles at equilibrium

For 1 mol H2 we need 1 mol I2 to produce 2 moles of HI

Moles H2 = 0.714 - X

Moles I2 = 0.984 -X

Moles HI = 0.886 + 2X

Step 3: Define Kc

Kc = [HI]² / [I2][H2]

Kc = [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Kc =(n(HI)²) /(nH2 *nI2)

KC = 54.3 = (0.886+2X)² /((0.714 - X)*(0.984 -X))

X = 0.548

Step 4: Calculate concentrations at the equilibrium

[H2] = (0.714-0.548) / 2.40 = 0.0692 M

[I2] = (0.984 - 0.548) / 2.40 = 0.182 M

[HI] = (0.886+2*0.548) /2.40 = 0.826 M

6 0

3 years ago

Read 2 more answers

How many hydrogen atoms are in each molecule of trisilylamine?

lord [1]

Answer:

9

Explanation:

The amine functional group is obtained by subsititution of one or more hydrogen atoms in the ammonia compound.

Ammonia is NH₃.

Then,

by substituting one hydrogen you obtain R - NH₂.

by substituting two hydrogens you obtain R' - NH - R''

by subsituting the three hydrogens you obtain:

R'''

R' - N - R''

In this case, the three subsitutuents are silyl groups. The silyl group is derived form silane and is SiH₃. So, the tcompound trisilylamine is:

SiH₃

SiH₃ - N - SiH₃

Thus, you can count 3 hydrogen atoms for every silylgroup for a total of 9 hydrogen atoms in each molecule of trisilylamine.

7 0

4 years ago