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boyakko [2]
3 years ago
7

How do I work this -(-3)-[-(-4]-2+7

Mathematics
1 answer:
OLga [1]3 years ago
4 0

Answer:

<h2>4</h2>

Step-by-step explanation:

-(-3)-[-(-4)]-2+7 = 3 - [4] - 2 + 7 = 3 - 4 - 2 + 7 = (3+7) - (4+2) = 10 - 6 = 4

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What is the area of a sector with radius 4 and an angle of 18°? Use 3.14 for pi.
iVinArrow [24]
The area of the sector (As) of a circle may be calculated by the formula,
                                     As = (a / 360) x π x r²
where a is the measure of angle in degrees and r is the radius. Substituting the known values, 
                                    As = (18 / 360) x 3.14 x (4²) = 2.512
Thus, the area of the sector is approximately 2.512 squared units.

8 0
3 years ago
Read 2 more answers
Simplify (b^4)^3. ❤️ SLAT*_^}
KiRa [710]

Answer:

b^1^2

Step-by-step explanation:

<em>First, multiply by exponent rule.</em>

<em>(x^y)^z=x^y^z</em>

<em>b^4^*^3</em>

<em>Then, multiply by the numbers from left to right.</em>

<em>4*3=12</em>

<em>b^1^2, </em><em>is the correct answer. </em>

6 0
3 years ago
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Find the value of [-3/7] raised to the power -2<br><br> and (3) raised to the power -4
xenn [34]
(3)^-4 = 0.01234567901
(-3/7)^-2 = <span>5.44444444444</span>

7 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
dusya [7]

1)

(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}

3)

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}

7 0
3 years ago
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Divide using polynomial long division.<br> 2. (x² + 7x +44) = (x +4)
UkoKoshka [18]

Answer:

the answer is given in the photo below

4 0
3 years ago
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