Answer:
87.08% percentage of families spend more than $4000 annually on food and drink
Step-by-step explanation:
Given -
average annual expenditure on food and drink for all families is $5700
Mean
= 5700
standard deviation
= 1500
Let X be the no of families spend annually on food and drink
percentage of families spend more than $4000 annually on food and drink =
= 
=
Using 
= 1 - 
= 1 - .1292
= .8708
= 87.08%
Answer:
we're is the answer
Step-by-step explanation:
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