Answer:
a. 55 hours
b. 1.9 degrees C
Step-by-step explanation:
This means for each hour the temperature drops 0.08. This is the expression 0.08x where x is number of hours.
a.) If the temperature has dropped 4.4, then 4.4 = 0.08x. Solving for x will give the number of hours it takes to drop 4.4.
4.4 = 0.08x
4.4 / 0.08 = x
55 = x
b.) If the temperature after 55 hours and dropping 4.4 is -2.5, then the temperature at the start would be -2.5 + 4.4 = 1.9. The temperature at noon was 1.9 degrees celsius.
Answer:
x = 2i, x = -2i and x = 4 are the roots of given polynomial.
Step-by-step explanation:
We are given the following expression in the question:

One of the zeroes of the above polynomial is 2i, that is :

Thus, we can write

Now, we check if -2i is a root of the given polynomial:

Thus, we can write

Therefore,

Dividing the given polynomial:

Thus,

X = 4 is a root of the given polynomial.

Thus, 2i, -2i and 4 are the roots of given polynomial.
Answer:
First one should be 3 1/4 or 3.25
Step-by-step explanation:
What you do is count up the lines so in this case we have 4 lines so we do 100/4 = 25 so each line is 0.25 or 1/4 and since it's after 3 it should be 3 1/4 or 3.25
The maximum volume of the box is 40√(10/27) cu in.
Here we see that volume is to be maximized
The surface area of the box is 40 sq in
Since the top lid is open, the surface area will be
lb + 2lh + 2bh = 40
Now, the length is equal to the breadth.
Let them be x in
Hence,
x² + 2xh + 2xh = 40
or, 4xh = 40 - x²
or, h = 10/x - x/4
Let f(x) = volume of the box
= lbh
Hence,
f(x) = x²(10/x - x/4)
= 10x - x³/4
differentiating with respect to x and equating it to 0 gives us
f'(x) = 10 - 3x²/4 = 0
or, 3x²/4 = 10
or, x² = 40/3
Hence x will be equal to 2√(10/3)
Now to check whether this value of x will give us the max volume, we will find
f"(2√(10/3))
f"(x) = -3x/2
hence,
f"(2√(10/3)) = -3√(10/3)
Since the above value is negative, volume is maximum for x = 2√(10/3)
Hence volume
= 10 X 2√(10/3) - [2√(10/3)]³/4
= 2√(10/3) [10 - 10/3]
= 2√(10/3) X 20/3
= 40√(10/27) cu in
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