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OLEGan [10]
3 years ago
9

John was building a wall out of bricks the weight of the wall was 543.75

Mathematics
2 answers:
Ilya [14]3 years ago
8 0

Answer:

John was building a wall out of bricks. The weight of the wall was 543.75 pounds. Each brick weighed 4.35 pounds. How many bricks did John use?

Step-by-step explanation:

You have to divide.

adell [148]3 years ago
3 0
Is there a picture?
To go with this question?
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Volume is length times width times height so multiply those
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2 years ago
Jim's father is older than 40 but younger than 50. If you divide his age by 2, 4, 5, 8, or 10, there will be a remainder of 1, H
ExtremeBDS [4]

Answer:

41

Step-by-step explanation:

41:2= 20 with remainder of 1

41:4=10 r:1

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8 0
2 years ago
The mean area of homes in a certain city built in 2009 was 2438 square feet. Assume that a simple random sample of 11 homes in t
mr Goodwill [35]

Answer:

The p-value of the test is 0.029.

Step-by-step explanation:

The mean area of homes in a certain city built in 2009 was 2438 square feet.

An insurance company wants to know if the mean area of homes built in 2010 is less than that of homes built in 2009.

This means that at the null hypothesis we test if the mean is the same as in 2009, that is:

H_0: \mu = 2438

At the alternate hypothesis, we test that if it is less, than is;

H_a: \mu < 2438

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

2438 is tested at the null hypothesis:

This means that \mu = 2438

Assume that a simple random sample of 11 homes in the same city built in 2010 had a mean area of 2,293 square feet, with a standard deviation of 225 square feet.

This means that n = 11, X = 2293, s = 225

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{2293 - 2438}{\frac{225}{\sqrt{11}}}

t = -2.14

Compute the P-value of the test.

Probability of finding a mean less than a value(in this case, 2293) is a one-tailed test.

The pvalue is found for a one-tailed test, with t = -2.14 and 11 - 1 = 10 degrees of freedom. With the help of a calculator, the pvalue of the test is of 0.029

The p-value of the test is 0.029.

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Explain how would you find the square root of a number​
nirvana33 [79]

Answer:

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Step-by-step explanation:

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