When protecting a worksheet all cells are locked by default.?

a. displays the sum of all even numbers between 2 and 100 (inclusive). b. displays the sum of all squares between 1 and 100 (inc

LuckyWell [14K]

Answer:

The program required is in the explanation segment.

Explanation:

Program :

import math

# a. displays the sum of all even numbers between 2 and 100 (inclusive).

print("All even numbers from 2 to 100 inclusive ")

sum=0

i=2

while i<=100:

if i %2 ==0:

sum=sum+i

print(i,end=" ")

i=i+1

print("\nThe sum of all even numbers between 2 and 100 (inclusive) :",sum);

#b. displays the sum of all squares between 1 and 100 (inclusive).

print("\nAll squares numbers from 1 to 100 inclusive:")

i=1

sum=0

while i<=100:

print(i*i,end=" ")

i=i+1

sum=sum+(i*i)

print("\n\nThe sum of all squares between 1 and 100 (inclusive) is :",sum)

#c. displays the powers of 2 from 1 up to 256.

print("\nAll powers of 2 from 2 ** 0 to 2 ** 8:")

i=0

while True:

p=math.pow(2,i)

if p>256:

break

print("2 ** ",i," is ",int(p))

i=i+1

#d. displays the sum of all odd numbers between a and b (inclusive), where a and b are inputs

print("\nCompute the sum of all odd integers between two intgers ")

a=int(input("Enter an integer:"))

b=int(input("Enter another integer: "))

count = 0

temp=a

sum=0

while a<=b:

if a%2!=0:

print(a,end=" ")

sum=sum+a

a=a+1

print("\nThe total of the odd numbers from ", temp ," to ", b ,"is",sum)

#e.displays the sum of all odd digits of an input. (For example, if the input is 32677, the sum would be 3 + 7 + 7 = 17.)

print("\nCompute the sum of the odd digits in an integer ")

n=int(input("Enter an integer:"))

count=0

sum=0

temp=n

while n!=0:

rem = n%10

if rem%2!=0:

sum=sum+rem

count=count+1

n=int(n/10)

print("Sum of the odd digits is ",sum)

print("The total of the odd digits in ",temp," is ",count)

4 0

3 years ago

The first mechanical computer design in by Charles Babbage was Called

White raven [17]

Answer:

<h2>Analytical Engine</h2>

Explanation:

Analytical Engine, generally considered the first computer, designed and partly built by the English inventor Charles Babbage in the 19th century (he worked on it until his death in 1871).

7 0

3 years ago

Read 2 more answers

How much cell phone data does the average person use a month

azamat

It all depends on what you're doing online.

7 0

3 years ago

Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static

yKpoI14uk [10]

Answer:

Hope this helped you, and if it did , do consider giving brainliest.

Explanation:

import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

// main method

public static void main(String[] args) {

// create a list of Comparable type

List<Comparable> list = new ArrayList<>();

// add elements

list.add(1);

list.add(2);

list.add(3);

list.add(4);

list.add(5);

list.add(6);

list.add(7);

// print list

System.out.println("\nList : "+list);

// test search method

Comparable a = 7;

System.out.println("\nSearch for 7 : "+search(list,a));

Comparable b = 3;

System.out.println("\nSearch for 3 : "+search(list,b));

Comparable c = 9;

System.out.println("\nSearch for 9 : "+search(list,c));

Comparable d = 1;

System.out.println("\nSearch for 1 : "+search(list,d));

Comparable e = 12;

System.out.println("\nSearch for 12 : "+search(list,e));

Comparable f = 0;

System.out.println("\nSearch for 0 : "+search(list,f));

}

// static method named search takes arguments Comparable list and Comparable parameter

public static boolean search(List<Comparable> list, Comparable par) {

// if list is empty or parameter is null the throw IllegalArgumentException

if(list.isEmpty() || par == null ) {

throw new IllegalArgumentException();

}

// binary search

// declare variables

int start=0;

int end =list.size()-1;

// using while loop

while(start<=end) {

// mid element

int mid =(start+end)/2;

// if par equal to mid element then return

if(list.get(mid).equals(par) )

{

return true ;

}

// if mid is less than parameter

else if (list.get(mid).compareTo(par) < 0 ) {

start=mid+1;

}

// if mid is greater than parameter

else {

end=mid-1;

}

// if not found then retuen false

return false;

}

}import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

// main method

public static void main(String[] args) {

// create a list of Comparable type

List<Comparable> list = new ArrayList<>();

// add elements

list.add(1);

list.add(2);

list.add(3);

list.add(4);

list.add(5);

list.add(6);

list.add(7);

// print list

System.out.println("\nList : "+list);

// test search method

Comparable a = 7;

System.out.println("\nSearch for 7 : "+search(list,a));

Comparable b = 3;

System.out.println("\nSearch for 3 : "+search(list,b));

Comparable c = 9;

System.out.println("\nSearch for 9 : "+search(list,c));

Comparable d = 1;

System.out.println("\nSearch for 1 : "+search(list,d));

Comparable e = 12;

System.out.println("\nSearch for 12 : "+search(list,e));

Comparable f = 0;

System.out.println("\nSearch for 0 : "+search(list,f));

}

// static method named search takes arguments Comparable list and Comparable parameter

public static boolean search(List<Comparable> list, Comparable par) {

// if list is empty or parameter is null the throw IllegalArgumentException

if(list.isEmpty() || par == null ) {

throw new IllegalArgumentException();

}

// binary search

// declare variables

int start=0;

int end =list.size()-1;

// using while loop

while(start<=end) {

// mid element

int mid =(start+end)/2;

// if par equal to mid element then return

if(list.get(mid).equals(par) )

{

return true ;

}

// if mid is less than parameter

else if (list.get(mid).compareTo(par) < 0 ) {

start=mid+1;

}

// if mid is greater than parameter

else {

end=mid-1;

}

// if not found then retuen false

return false;

}

7 0

2 years ago

Think of a simple software project that requires your design skills. Specify the requirements needed on each design process

andrew-mc [135]

Answer:In this guide, we'll go over the basics of your software development ... I know which option I'd choose. ... Will you need to integrate with other tools or APIs? ... With the requirements in place, it's time to start designing what this ... In its most basic form, you can think of the Waterfall method as following each ...

Explanation:

4 0

3 years ago