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IrinaK [193]
3 years ago
11

PLS HELP ME,I'LL MARK U AS BRAINLIEST IF U HELP ME!!!! 1. Write the algebraic expressions of the following. a) Twice of a number

added to 5 b) difference of the squares of two numbers m and n multiplied by 6 c) r cubed minus y squared d) five times x raised to the power of 5 added to twice of y cubed
Mathematics
2 answers:
Savatey [412]3 years ago
8 0

Step-by-step explanation:

Let the number be x

(a) 2x + 5

(b) (m²-n²) × 6

(c) r³-y²

(d)

5 {x}^{5}  + 2 {y}^{2}

harina [27]3 years ago
7 0

Step-by-step explanation:

a)

Twice of a number added to 5.

Let the number be n.

Twice of the number: 2n

Twice of the number added to 5: 2n+5

b)

Difference of squares of m and n multiplied by 6.

Difference of squares: m^{2} -n^{2}

Difference of squares multiplied by 6: 6(m^{2} -n^{2} )

c)

r cubed minus y squared

r cubed: r^{3}

y squared: y^{2}

r cubed minus y squared: r^{3} -y^{2}

d)

Five times of x raised to the power of 5 added to twice of y cubed

Five times of x raised to the power of 5: 5x^{5}

Twice of y cubed: 2y^{3}

Five times of x raised to the power of 5 added to twice of y cubed:

5x^{5} +2y^{3}

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Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3

• Put eqn 3 in eqn 2

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Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

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The 95% confidence interval for the average satisfaction score is computed as:

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This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

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(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

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Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
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Determine the currents in the picture
Elenna [48]

Answer:

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Step-by-step explanation:


The Ohm's law states that

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In a parallel circuit:

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I_2=I_1+I_3                   .... (1)

Equation for first loop is,

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Equation for second loop is,

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