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faltersainse [42]
3 years ago
9

What is the quotient (x3 + 6x2 + 11x + 6) ÷ (x2 + 4x + 3)? x + 2 x – 2 x + 10 x + 6

Mathematics
2 answers:
sveta [45]3 years ago
5 0
If you would like to solve (x^3 + 6x^2 + 11x + 6) / (x^2 + 4x + 3), you can do this using the following steps:

(x^3 + 6x^2 + 11x + 6) / (x^2 + 4x + 3<span>) = ((x + 1) * (x + 2) * (x + 3)) / ((x + 1) * (x + 3)) = x + 2
</span>
The correct result would be x + 2.
ratelena [41]3 years ago
4 0
Hello,

Answer A

x²+4x+3=(x+3)(x+1)

x^3+6x²+11x+6=(x+1)(x²+5x+6)

x²+5x+6=(x+2)(x+3)

so

x^3+6x²+11x+6=(x+1)(x+2)(x+3) (Horner's method)


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An individual saves $5000 in a bank account at the beginning of each year for 10 years.
frozen [14]

Answer:

a) Amount saved if the interest is compounded annually is $5832

b) Amount saved if the interest is compounded semi-annually is $5849.5

Step-by-step explanation:

Principal Amount P = 5000

Time t = 10 years

Annual interest i = 8% = 0.08

We need to find amount saved if interest is compounded a) annually b) semi-annually

a) Amount saved if the interest is compounded annually

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Using Formula: A=P(1+\frac{r}{n})^{nt}

Putting values:

A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{1})^{1*2}\\A=5000(1+0.08)^2\\A=5000(1.08)^2\\A=5000(1.1664)\\A=5832

So, Amount saved if the interest is compounded annually is $5832

b) Amount saved if the interest is compounded semi-annually

If interest compounded semi-annually, n= 2

Using Formula: A=P(1+\frac{r}{n})^{nt}

Putting values:

A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{2})^{2*2}\\A=5000(1+0.04)^4\\A=5000(1.04)^4\\A=5000(1.1699)\\A=5849.5

So, Amount saved if the interest is compounded semi-annually is $5849.5

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