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3 years ago

How many different triangles can be constructed with side measurement 6 cm 9 cm and 13 cm

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

4 0

Answer:

A. Exactly one triangle

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(2/7)power 7 divided (2/7)power 5

Harrizon [31]

Answer:

4/49

Step-by-step explanation:

7-5 = 2

2/7*2/7 = 4/49

6 0

3 years ago

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Describe a situation that is defined by the linear equation P = 40 + 22t.

sashaice [31]

The situation that is defined by the linear equation P = 40 + 22t is "The initial amount is 40 and the rate of change is 22".

<h3>What is a linear equation?</h3>

Given:

P = 40 + 22t

where,

P = total price
40 = initial amount
22 = rate of change
t = number of rate of change

So,

if t = 3

P = 40 + 22t

= 40 + 22(3)

= 40 + 66

P = 106

Therefore, the initial amount is 40 and the rate of change is 22 describes the linear equation P = 40 + 22t

Learn more about linear equation:

brainly.com/question/14323743

4 0

2 years ago

Help me pleaseeeee<br> :))))

krok68 [10]

-6/7 (Hope it helps)

5 0

3 years ago

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Help question attached multiple choice

Rina8888 [55]

ANSWER

$x = \frac{\pi}{2} , \frac{7\pi}{6} , \frac{3\pi}{2} , \frac{11\pi}{6}$

EXPLANATION

The given trigonometric equation is

$\cos(x) + 2 \cos(x) \sin(x) = 0$

We factor cos(x) to get:

$\cos(x) (1 + 2 \sin(x) ) = 0$

Apply the zero product property to obtain:

$\cos(x) = 0 \: or \: 1 + 2 \sin(x) = 0$

$\cos(x) = 0 \: or \: \sin(x) = - \frac{1}{2}$

Using the unit circle,

$\cos(x) = 0$

when

$x = \frac{\pi}{2}$

and

$x = \frac{3\pi}{2}$

We know

$\sin(y) = \frac{1}{2}$

when

$y= \frac{\pi}{6}$

The sine function is negative in the third and fourth quadrants.

$x = \pi + \frac{\pi}{6} = \frac{7\pi}{6}$

$x = 2\pi - \frac{\pi}{6} = \frac{11\pi}{6}$

Hence the solutions are:

$x = \frac{\pi}{2} , \frac{7\pi}{6} , \frac{3\pi}{2} , \frac{11\pi}{6}$

6 0

3 years ago

X + 2/3 = 8/9 x=__ ..........................................

stepladder [879]

Answer:

x = -6

Step-by-step explanation:

$x+\frac{2}{3}=\frac{8}{9}x\\\\x = \frac{8}{9}x - \frac{2}{3}\\\\x - \frac{8}{9}x= -\frac{2}{3}\\\\\frac{9}{9}x-\frac{8}{9}x=\frac{2}{3}\\\\\frac{1}{9}x=-\frac{2}{3}\\\\x=-\frac{2}{3}*\frac{9}{1}\\\\x=(-2)*3\\\\x = -6$

6 0

2 years ago

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