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expeople1 [14]
3 years ago
9

Factor 6(2p q)^2 -5(2p q) - 25

Mathematics
1 answer:
kherson [118]3 years ago
3 0
Treat the 2p+q as x

6x2-5x-25
trial and error
(2x-5)(3x+5)
replace x with (2p+q)
(2(2p+q)-5)(3(2p+q)+5)
(4p+2q-5)(6p+3q+5)
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More math help pls. :)
Step2247 [10]

By using trigonometric relations, we will see that x = 9.97°.

<h3>How to find the missing angle?</h3>

First, we need to find the bottom cathetus of the smaller triangle, we will use the relation:

Tan(θ) = (opposite cathetus)/(adjacent cathetus).

Where:

  • θ = 26°
  • Adjacent cathetus = k
  • Opposite cathetus  = 55ft.

Replacing that we get:

Tan(26°) = 50ft/k

Solving this for k, we get:

k = 55ft/tan(26°) = 112.8 ft

Now, we can see that the longer triangle adds 200ft to this cathetus, so now we will have:

  • angle = x
  • opposite cathetus = 55ft
  • adjacent cathetus = 112.8ft + 200ft = 312.8ft.

Then we have:

Tan(x) = (55ft/312.8ft)

Using the inverse tangent function in both sides, we get:

x = Atan(55ft/312.8ft) = 9.97°

If you want to learn more about right triangles, you can read:

brainly.com/question/2217700

6 0
2 years ago
A cylinder has a volume of 2457 cubic units and a height of 5 units. The diameter of the cylinder is?
Bond [772]

Answer:14

Step-by-step explanation:

3 0
3 years ago
Sadie wants to paint 2 boxes. The paint costs $0.02 cents per square cm. If she throws the lids away, how much will it cost to p
Alex

Answer:

how many square centimeters is the box??

Step-by-step explanation:

8 0
3 years ago
The rectangle shown represents the base of a cracker box shaped like a rectangular prism. Use the ruler provided to measure the
malfutka [58]

There is no rectangle shown, nor ruler given to measure and attempt your work. Nevertheless, I will illustrate how to find the volume of a rectangular prism.

Step-by-step explanation:

Given a rectangular prism of sides

Length = l

Width = w

Height = h

The volume of this prism is given as

V = l × b × h.

Example, if

Length = 4cm

Width = 3cm

Height = 2cm

Volume = 4 × 3 × 2

= 24cm³.

7 0
3 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
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