Answer:
5 units
Step-by-step explanation:
According to the given statement Δ XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z' which means that each point in ΔXYZ is moved 4 units up and moved 3 units left.
To find the distance of each corresponding point we will use the Pythagorean theorem which states that the square of the length of the Pythagorean of a right triangle is equal to the sum of the squares of the length of other legs
The square of the required distance = 4^2+3^2 = 16+9 =25
By taking root of 25 we get:
√25 = 5
Thus, we can conclude that the the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′ is 5 units.
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Answer:
-37.5 m
Step-by-step explanation:
If we assume that "one full day" is 24 hours, then 15 hours represents the fraction 15/24 of a day. Since the drilling rate was constant, and was presumed to start from a height of 0, the height after 15 hours is that fraction of the day's work:
... (15/24)×(-60 m) = -37.5 m
If we assume the club membership includes

then the blanks in the Juniors circle must be filled in with 6 and 8 (with the 8 going in the overlap with girls). The remaining blank in the Girls circle must be filled in with 12, the number of senior girls. The blank outside both circles is the number of senior boys (members who are not juniors and not girls), 16.