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andrew11 [14]
3 years ago
8

Jill Barkley obtained a 25 year 460,000$ mortgage loan with 6% interest for the first payment fund the new balance to the neares

t cent
Mathematics
1 answer:
vovikov84 [41]3 years ago
7 0
The answer is 520,597.55                                  
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I had $3.00. My Mom gave me $10.00. My Dad Gave me $30.00. My Aunt & Uncle gave me $100.00. I had another $7.00. How much di
zysi [14]

Answer:

150

Step-by-step explanation:

i did addition so yeah

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3 years ago
Joe bought a $40 video game for only $28, what was the percent discount on<br> the item?
Nata [24]

Answer:

30 % off

Step-by-step explanation:

12 dollars off of 40

40 (x) = 12

x = 12/40 = .3     or  30 %

6 0
1 year ago
Alan bought a suit on sale for $208. This price was 35% less than the original price.
algol [13]

Answer:

280.8

Step-by-step explanation:

Since 100% is the full amount, and it is 35% off you add 35 to the 100. So you get 1.35. You finally multiply by 207 and get 280.8

7 0
3 years ago
1. A gambler makes 100 column bets at roulette. The chance of winning on any one play is 12/38. The gambler can either win $ 5 o
lapo4ka [179]

Answer:

a) Expected amount of the gambler's win = $0.209

b) SD = 2.26

c)P (X >1) = P(z >0.35) = 0.36317

Step-by-step explanation:

The probability of winning, p = 12/38 =6/19

Probability of losing, q = 1 -p = 1-6/19

q = 13/19

Win amount = $5

Loss amount = $2

a) Expected total amount of win = ((6/19)*5) - ((13/19)*2)

Expected total amount of win = 1.579 - 1.369

Expected amount of win, E(X) = $0.209

b) Standard Deviation for the total amount of the gambler's win

SD = \sqrt{E(X^{2}) - (E(X))^{2} }

E(X²) = (6/19)*5²  -  (13/19)*2²

E(X²) = 5.158

SD = \sqrt{5.158 - 0.209^2}

SD = 2.26

c)  probability that, in total, the gambler wins at least $1.

P(X >1)

z = \frac{X - \mu}{\sigma}

μ = E(x) = 0.209

z = (1-0.209)/2.26

z = 0.35

P( X >1) = P(z >0.35)

P(z >0.35) = 1 - P(z <0.35)

P(z >0.35) = 1 - 0.63683

P(z >0.35) = 0.36317

5 0
3 years ago
How to write 309,099,990 in word
Alina [70]
Three-hundred and nine million, ninety-nine thousand, nine-hundred and ninety
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3 years ago
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