For a two-digit number to be palindromic, the two digits must be the same.
Number of two-digit numbers with the two digits equal is 9. (i.e. 11, 22, 33, . . . )
Total number of two-digit numbers is 90.
Therefore, the <span>probability that a randomly chosen two-digit number is palindromic is 1 / 10 or 0.1.</span>
Answer:
The solution to the system of equations should be (-1,1)
Step-by-step explanation:
Answer:lol
Step-by-step explanation:
hahaha
I think the best answer would be answer D
Answer:
Step-by-step explanation:
Enter a problem...
Algebra Examples
Popular Problems Algebra Solve for x 64^(4x)=16^(x+1)
64
4
x
=
16
x
+
1
Create equivalent expressions in the equation that all have equal bases.
4
3
(
4
x
)
=
4
2
(
x
+
1
)
Since the bases are the same, then two expressions are only equal if the exponents are also equal.
3
(
4
x
)
=
2
(
x
+
1
)
Solve for
x
.
Tap for fewer steps...
Multiply
4
by
3
.
12
x
=
2
(
x
+
1
)
Simplify
2
(
x
+
1
)
.
Tap for fewer steps...
Apply the distributive property.
12
x
=
2
x
+
2
⋅
1
Multiply
2
by
1
.
12
x
=
2
x
+
2
Move all terms containing
x
to the left side of the equation.
Tap for fewer steps...
Subtract
2
x
from both sides of the equation.
12
x
−
2
x
=
2
Subtract
2
x
from
12
x
.
10
x
=
2
Divide each term by
10
and simplify.
Tap for fewer steps...
Divide each term in
10
x
=
2
by
10
.
10
x
10
=
2
10
Cancel the common factor of
10
.
Tap for fewer steps...
Cancel the common factor.
10
x
10
=
2
10
Divide
x
by
1
.
x
=
2
10
Cancel the common factor of
2
and
10
.
Tap for fewer steps...
Factor
2
out of
2
.
x
=
2
(
1
)
10
Cancel the common factors.
Tap for fewer steps...
Factor
2
out of
10
.
x
=
2
⋅
1
2
⋅
5
Cancel the common factor.
x
=
2
⋅
1
2
⋅
5
Rewrite the expression.
x
=
1
5
The result can be shown in multiple forms.
Exact Form:
x
=
1
5
Decimal Form:
x
=
0.2
