All categories

3 years ago

I need help on this I don’t know what to do

Mathematics

1 answer:

nadya68 [22]3 years ago

8 0

Answer:

x=9

Step-by-step explanation:

logx (531441) = 6

Changing this to an exponential

x^6 =531441

Take the 6th root of each side

(x^6)^1/6 = (531441)^1/6

x =9

You might be interested in

He equation for the circle is: x2+y2−12x+6y−19=0 . What is the center of the circle?

vaieri [72.5K]

The center of the circle is (6,-3)
Hope this helped :)

3 0

4 years ago

What will be the annual salary for a mechanic who works 40 hours per week for 52 weeks a year and makes $25.21 per hour? (Rememb

Snowcat [4.5K]

Salary = 40hrs x 52wks x $25.21

= $<span>52,436.80 per year</span>

5 0

3 years ago

How many squares do I have to draw in(10 x 10 grid) for the percentage of 57.74%??

Afina-wow [57]

Answer:

There is obviously only 1 10x10 square. If we start with a 9x9 square in the top left corner, we can move it down 1, across 1 and back up 1, so there are 4 possible 9x9 squares.

For 8x8 we can move down 1, then 2 and we can move across 1 or 2 so that's 9 possible 8x8 squares.

For 7x7 we can go down 3 and across 3, so that's 4x4=16 possible squares.

The pattern is now clear the total number if squares is 1+4+9+16+…+100.

There's a formula for this, which I had to look up, but any the sum of the first n squared is 1/6n(n+1)(2n+1)1/6n(n+1)(2n+1), so the total number of squares is 10x11x21/6=5x11x7=385.

6 0

3 years ago

If (tan^3 theta -1) / (tan theta - 1) - sec^2 theta +1 = 0, find cot theta.

stiv31 [10]

Hey there !

Check the attachment.
Hope it helps you :)

7 0

3 years ago

Read 2 more answers

The length of a chord is equal to its distance to the center of the circle. A second chord in the same circle is twice as long a

Rama09 [41]

Answer:

The distance from the center of the circle to the longer chord is twice smaller than the distance from the center to the shorter chord.

Step-by-step explanation:

The length of the chord AB is the same as the distance OC from the center to the cord. Let OC=2x, then CA=x. By the Pythagorean theorem, the radius r of the circle is

$r^2=OC^2+AC^2,\\ \\r^2=(2x)^2+x^2=5x^2,\\ \\r=\sqrt{5}x.$

The length of the arc ED is 4x.

Consider right triangle EFO. In this triangle, EF=2x, EO=r, then the distance OF is

$OF^2=OE^2-EF^2,\\ \\OF^2=5x^2-(2x)^2=x^2,\\ \\OF=x.$

The distance from the center of the circle to the longer chord is twice smaller than the distance from the center to the shorter chord.

5 0

4 years ago