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Sever21 [200]
3 years ago
12

WHY IS THIS GETTING DELETED?? I NEED HELP

Mathematics
1 answer:
aliina [53]3 years ago
3 0

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

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Answer:

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Step-by-step explanation:

8 0
4 years ago
PLEASE HELP FAST!!
Mice21 [21]

Answer:

  • 367.6 m

Step-by-step explanation:

Use trigonometry

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8 0
3 years ago
If h(x) = x – 7 and g(x) = x2, which expression is equivalent to (g circle h) (5)?
Tema [17]
<h3>Answer:  4</h3>

=====================================================

Work Shown:

(g \circ h)(x) = g(h(x))

g(x) = x^2\\\\g(h(x)) = (h(x))^2 \ \text{replace every x with h(x)}\\\\g(h(x)) = (x-7)^2 \ \text{replace h(x) with x-7}\\\\(g \circ h)(x) = (x-7)^2

Now plug in x = 5

(g \circ h)(x) = (x-7)^2 \\\\(g \circ h)(5) = (5-7)^2 \\\\(g \circ h)(5) = (-2)^2\\\\ (g \circ h)(5) = 4

---------------------

Alternative approach:

h(x) = x-7

h(5) = 5-7

h(5) = -2

So this means

g(h(5)) = g(-2)

and

g(x) = x^2

g(-2) = (-2)^2

g(-2) = 4

Therefore making

g(-2) = g(h(5)) = (g \circ h)(5) = 4

8 0
4 years ago
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The light in the transformed flowerbed is at coordinate ________
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Step-by-step explanation:

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Step-by-step explanation:

3 0
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