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3 years ago

15

jared attempted 20 free throws during basketball practice. He made 16 of his shots and missed the rest. What percentage of the f

ree throws did jared miss?

2 answers:

Akimi4 [234]3 years ago

6 0

The answer is 20% because 4/20 equals 1/5 which is 20%

Ivanshal [37]3 years ago

3 0

20 - 16 = 4 missed shots

4/20 missed

Multiply by 5/5

4/20 * 5/5 = 20 / 100 = 20%

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Help please !!:) For y =3x -2x^2 +5x^3 show how to find the value for y when x = 3

victus00 [196]

y = 3x-2x∧2+5x∧3

When we replace x with value 3 we get

y = 3 * 3 - 2 * 3∧2 + 5 * 3∧3 => y = 9-2*9+5*27 => y = 9-18+135 => y = 126

good luck!!!

7 0

4 years ago

A pizza place offers 3 different cheeses and 12 different toppings. In how many ways can a pizza be made with 1 cheese and 3 top

svetlana [45]

You have to choose 1 sort of cheese from 3 ( 3 ways ). Also you have to choose 3 toppings from 12 different toppings:
12 * 11 * 10 = 1,320 ways.
In total: 3 * 1,320 = 3,960
Answer:
In 3,690 ways can pizza be made with 1 cheese and 3 toppings.

3 0

3 years ago

Ratio equal to 90:18

Vadim26 [7]

90:18

divide using 3 on both sides

90:18

30:6

10:2

now lets use 2

10:2

5:1

5:1 is the equal ratio to 90:18

6 0

4 years ago

What is a common factor called

zlopas [31]

<span>A common factor is a factor of 2 or more numbers.
the factors of 12 are: 1,2,3,4,6,12
the factors of 21 are: 1,3,7,21

1 and 3 are both common factors of 12 and 21.</span>

7 0

3 years ago

V. Money Magazine reported that the average price of gasoline in the United States during the first quarter of 2008 was $3.46. A

Butoxors [25]

Answer:

$z=\frac{3.43 -3.46}{\frac{0.15}{\sqrt{30}}} = -1.095$

$z=\frac{3.49 -3.46}{\frac{0.15}{\sqrt{30}}} = 1.095$

And we can find this probability using the normal standard table and we got:

$P(-1.095$

Step-by-step explanation:

Let X the random variable that represent the price of a population, and for this case we know the distribution for X is given by:

$X \sim N(3.46,0.15)$

Where $\mu=3.46$ and $\sigma=0.15$

And for this case we want to find the following probability:

$P(3.43 \leq \bar X \leq 3.49)$

And we can use the z score formula given by:

$z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

If we find the z score for the limits we got:

$z=\frac{3.43 -3.46}{\frac{0.15}{\sqrt{30}}} = -1.095$

$z=\frac{3.49 -3.46}{\frac{0.15}{\sqrt{30}}} = 1.095$

And we can find this probability using the normal standard table and we got:

$P(-1.095$

8 0

4 years ago