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elena-s [515]
3 years ago
9

(QUICK RESPONSE!) The perimeter of the original rectangle is 16 feet.

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

C

Step-by-step explanation:

We can see that the length of the enlarged rectangle is double the original. So, all of the lengths are doubled. Therefore, the perimeter of the larger rectangle is also doubled

16*2 = 32

frozen [14]3 years ago
7 0
The answer is 32,hope this helps
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Which of the following represents the sum 3+(-7)? Assume that red tiles represent negative numbers and blue tiles represent posi
Travka [436]

Answer:

were you supposed to attach a photo because I cant see it? All I can tell you 3+(-7)= -4

Step-by-step explanation:

8 0
3 years ago
Twins James and Jamie are getting bunk beds.their parents picked up the box from ruthand found that has dimensions of 6' x 2' x
Oksana_A [137]

The box with the bunk bed will not fit in the mini van

Step-by-step explanation:

Step 1 :

Given

Length of the cuboid  = 6 feet

Width of the cuboid  = 2 feet

Height of the cuboid = 3 feet

The diagonal of the cuboid is

\sqrt{l^{2}+w^{2}+h^{2}} = \sqrt{6^{2}+2^{2}+3^{2}}\\= \sqrt{49}

= 7 feet

Step 2 :

The utmost length of the diagonal of the box which the minivan can hold is 6.8 feet

The length of the diagonal of the box containing the bunk bed is 7 feet which is greater than 6.8 feet.

Hence the trunk of the mini van cannot hold the bunk bed

5 0
3 years ago
The average age of three people running for election is 42. A fourth person joins the race and the average drops to 40. What is
Morgarella [4.7K]

Answer:

B. 34

let \: sum \: of  \: ages \: of\: 3 \: people \: be \: x \\ 42 =  \frac{x}{3}  \\ x = 126 \\ let \:age \: of \:  fourth \: person \: be \: y \\ 40 =  \frac{x + y}{4}  \\ 160 = x + y \\ 160 = 126 + y \\ y = 34 \\  = 34 \: years

7 0
3 years ago
Find the area enclosed between f(x)=0.3x2+7 and g(x)=x from x=−4 to x=8.
denis23 [38]
First, we sketch a picture to get a sense of the problem. g(x)=x is a diagonal line through (0,0) with slope = = 1. Since we are interested in the area between x = -4 and x = 8, we find the points on the line at these values. These are (-4, -4) and (8,8).

f(x) is a parabola. It's lowest point occurs when x = 0. It is the point (0,7). At x = -4 and x=8 it has the values 11.8 and 26.2 respectively. That is, it contains the points (-4, 11.8) and (8,26.2).

From these we make a rough sketch (see attachment). This is a sketch and mine is very incorrect when it comes to scale but what matters here is which of the curves is on top, which is below and whether they intersect anywhere in the interval, so my rough sketch is good enough. From the sketch we see that f(x) is always above (greater than) g(x).

To find the area between the curves over the given interval we integrate their difference and since f(x) is strictly greater than g(x) we subtract as follows: f(x) - g(x). The limits of integration are the values -4 and 8 (the x-values between which we are looking for the area.

Now let's integrate:
\int\limits^{8}_ {-4}f(x)-g(x) \, dx = \int\limits^{8}_ {-4}.3 x^{2} +7-x \, dx
The integral yields: [tex](\frac{.3 (8)^{3} }{3} +7(8)- \frac{ (8)^{2} }{2}) -(\frac{.3 (-4)^{3} }{3} +7(-4)- \frac{ (-4)^{2} }{2}) = 117.6 [/tex]
We evaluate this for 8 and for -4 subtracting the second FROM the first to get:


4 0
3 years ago
In the figure below what is the value of x
LenaWriter [7]

Answer:

It would be 32. my G

3 0
3 years ago
Read 2 more answers
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