Answer:
2
Step-by-step explanation:
You count terms that are seperated by - and + signs. Any type of fraction is considered one term.
So you count 8y as one term and the rest is a whole fraction so you also count that as one term.
You add all the terms together and you have 2 terms in this equation.
Hope this helped :)
<span>The answer is The total area of the top and bottom squares. s = √7 cm is irrational value and we need rational value. Let's check all choices: A. The volume. V = (s)^3. If s = √7, V = (√7)^3 = 7√7 - irrational value. B. The perimeter of the front square. P = 4 * s = 4 * √7 = 4√7 - irrational value. C. The diagonal of the back square. d = s√2 = √7 * √2 = √(7*2) = √14 - irrational value. D. The total area of the top and bottom squares. A = 2 * s^2 = 2 * (√7)^2 = 2 * 7 = 14 - rational value.</span>
The value of x is an int with value 1.
The correct option is (A).
<h3>What is / in python?</h3>
Divides the value on the left by the one on the right.
<h3>What is // in python?</h3>
Divides and returns the integer value of the quotient.
x= 8/4//2
x= 2//2
x=1
Learn more about operators in python here:
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If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.
Value of X is 9 and Angle 6 is 79°
If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.
If two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.
If two parallel lines are cut by a transversal, then the pairs of alternate exterior angles are congruent.
Since, angle 1 and angle 4 are vertically opposite angles . Hence, these are equal.
∠1 = ∠4 = 11x + 2
Similarly, ∠6 and ∠7 are vertically opposite angles.
Thus, ∠6 = ∠7 = 8x + 7
If two parallel lines are cut by a transversal, then the sum of interior angles on one side is equal to 180 degree.
Therefore, ∠4 + ∠6 = 180
11x + 2 + 8x + 7 = 180
19x + 9 = 180
19x = 171
x = 9
Value of angle 6 = value of angle 7
= 8x + 7
= 8 (9) + 7
= 79 Degree
Learn more:
brainly.com/question/19670823
cos(2<em>θ</em>) + sin²(<em>θ</em>) = 0
Half-angle identity:
cos(2<em>θ</em>) + (1 - cos(2<em>θ</em>))/2 = 0
Simplify:
2 cos(2<em>θ</em>) + 1 - cos(2<em>θ</em>) = 0
cos(2<em>θ</em>) = -1
Solve for <em>θ</em> :
2<em>θ</em> = arccos(-1) + 2<em>nπ</em>
2<em>θ</em> = <em>π</em> + 2<em>nπ</em>
<em>θ</em> = <em>π</em>/2 + <em>nπ</em>
where <em>n</em> is any integer.