Given:
n = 195, sample size.
x = 162, successes in the sample
The proportion is
p = x/n = 162/195 = 0.8308
n* p = 195*0.8308 = 162
n*(1-p) = 195*(1 - 0.8308) = 33
If n*p >= 10, and n*(1-p) >= 10, then the sample proportions will have a normal distribution. This condition is satisfied.
The proportion mean is
μ = 0.8308
The proportion standard deviation is

σ/√n = 0.0269/√195 = 0.00192
At the 95% confidence level, the interval for the population proportion is
(μ - 1.96(σ/√n), μ + 1.96(σ/√n))
= (0.8308 - 1.96*0.00192, 0.8308 + 1.96*0.00192)
= (0.827, 0.8345)
Answer: The 95% confidence interval is (0.827, 0.835)
Answer:
a.
R-------8/38--------RR
R------9/39--------B-------13/38-------RB
G------17/38--------RG
R-------9/38--------BR
B--------13/39------B-------12/38-------BB
G-------17/38-------BG
R-----9/38--------GR
G---------17/39-------B------13/38-------GB
G------16/38-------GG
b).
- 9 ways
- ways you can select 1 blue are; RB,BR,BG,GB
RB=9/39 × 13/38=3/38
BR= 13/39 × 9/38 =3/38
BG= 13/39 × 17/38=17/114
GB= 17/39 × 13/38=17/114
=3/38 +3/38+17/114+ 17/114 =26/57
- Probability of selecting 2 red markers= RR = 9/39 × 8/38 =12/247
- Probability of selecting a green marker and then a red marker= GR= 17/39×9/38 =51/494
B because -3 times -2 is positive six.
Answer:
B. -6 and 7
Step-by-step explanation:
Answer:
Step-by-step explanation: