Quadratic inequalities

-8= 3-5(x+6) solving algebraicaily

SOVA2 [1]

Let's solve your equation step by step

-8=3-5(x+6)

Step 1: simplify both sides of the equation

-8=3-5(x+6)

-8=3+(-5)(x)+(-5(6) (distribute)

-8=3+-5x+-30

-8=(-5x)+(3+-30) (combine like terms)

-8=-5x+-27

-8=-5x-27

Step 2: flip the equation

-5x-27=-8

Step 3: add 27 to both sides

-5x-27+27=-8+27

-5x=19

Step 4: Divide both sides by -5

-5x/-5 = 19/-5

Answer : x= -19/5

4 0

4 years ago

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Select the equivalent expression.

Fittoniya [83]

Answer:

B

Step-by-step explanation:

8 0

3 years ago

What is 0.167 times 180

Agata [3.3K]

Answer:

30.06

Step-by-step explanation:

6 0

2 years ago

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Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

3 years ago

Two angles are supplementary. The measure of the larger angle is 4 more than 3 times the measure of the smaller angle. Find the

m_a_m_a [10]

Answer:

<u>The smaller angle measures 44° and the larger measures 136°</u>

Step-by-step explanation:

Let'e recall that supplementary angles are two angles whose sum is 180° degrees.

Smaller angle = x

Larger angle = 3x + 4

Therefore, we have:

x + 3x + 4 = 180

4x = 180 - 4

4x = 176

x = 176/4

x = 44 ⇒ 3x + 4 = 136

<u>The smaller angle measures 44° and the larger measures 136°</u>

5 0

3 years ago