Question

Can anyone help! WITH STEPS!

Answer 1

Answer:

When we have something like:

$\sqrt[n]{x}$

It is called the n-th root of x.

Where x is called the radicand, and n is called the index.

Then the term:

$\sqrt[4]{16}$

is called the fourth root of 16.

And in this case, we can see that the index is 4, and the radicand is 16.

At the end, we have the question: what is the 4th root of 16?

this is:

$\sqrt[4]{16} = \sqrt[4]{4*4} = \sqrt[4]{2*2*2*2} = 2$

The 4th root of 16 is equal to 2.