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erma4kov [3.2K]
3 years ago
14

BD bisects /ABC, Find m/ABC

Mathematics
1 answer:
gtnhenbr [62]3 years ago
3 0
The answer would be m/ABC = 15x+6




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I NEED SERIOUS HELP WITH THIS!
stich3 [128]

Answer:

-2

Step-by-step explanation:

The slope of a line is rise over run between two points.

In this line there is an upward rise of 2, and a horizontal run of -1.

Therefore the slope is just 2/-1 which is -2.

Hope this helps!

4 0
3 years ago
Read 2 more answers
Abraham is spending a day at the hotel pool. He enjoys jumping from the very cool pool (62 degrees) to the very hot Jacuzzi (113
Firlakuza [10]

Answer:

51

Step-by-step explanation:

113-62=51

3 0
3 years ago
5. What is the second step in proving by mathematical induction that for every positive integer n, 11" - 6 is divisible by
astraxan [27]

Answer:

The correct answer is A:Let n = k. Then assume that 11" - 6 is divisible by 5. sorry if im wrong but if correct pls mark brainliest

3 0
3 years ago
Read 2 more answers
Horses age more rapidly than humans.Suppose that the "horse age" and"human age"
Sav [38]

Let x represent the horse age

Let y represent the human age

Since the horse age and human age vary directly, we have the relation

x\text{ }\alpha\text{ y}

Introducing an equality sign, we

x\text{ =Ky}

Where K is a proportionality constant, evaluated as

K\text{ = }\frac{x}{y}----\text{ equation 1}

Since a 5-year-old horse is equivalent to 15-year old human,

x = 5

y = 15

we have

\begin{gathered} K\text{ = }\frac{5}{15} \\ \Rightarrow K=3 \end{gathered}

Thus,

\begin{gathered} K=\frac{x}{y} \\ 3\text{ = }\frac{x}{y} \\ \Rightarrow x\text{ = 3y ----- equation 2} \end{gathered}

Thus, for a horse who has lived 16 years

x = 16

4 0
1 year ago
PLS HELP WILL MARK BRAINLIEST!!!!!!!!<br> answer both questions (they are two separate questions)
Angelina_Jolie [31]

<u>Answer A is correct for both questions.</u>

Step-by-step explanation:

The area of the rectangle is lengthxwidth. To find the length, we can divide the area by the width.

\frac{(4x^2-43x+63)}{(4x-7)} is the equation.

We need to simplify it (or just divide). Since the coefficient of the area (on the x^2) is the same as that on the width, we know that that same coefficient on the length is 1.

This gets us to the basic frame (1x+/-y).

To find the value of y, we need to pay attention to the "-43x+63" and "-7" aspects of the area and width, respectively. To get "63," the "-7" was multiplied by the y — by dividing 63 by -7, we know that the value of y is -9 (the numbers both have to be negative to multiply to a positive number).

We are left with the length (x-9). Put together, this means (x-9)(4x-7) is the area. Multiplying, that makes (4x^2-7x-36x+63), or (4x^2-43x+63). Since this is the area given to us, we know our answer is correct. For this question, the answer is A.

*****

Divide 9x^4-2-6x-x^2 by 3x-1. First, put the first equation in order by exponents. We get \frac{9x^4-x^2-6x-2}{3x-1}. Since the exponent on the upper equation goes up to x^4, and we are dividing by a simple x, we know that the first exponent in our answer will be x^3. Since our coefficient needs to have a product of 9 when multiplied by 3, it is 3. The first part of our answer is (3x^3). Since there is no exponent of 3 for x in the upper equation, and since the "x^2" that has to be the next term in the equation due to it being present in each answer choice, we know that it as to be a "+x^2" — the "3x^3 that result from the "-1" (in the lower equation) being multiplied by 3x^3 have to be cancelled out by a "-3x^3", and if the sign for the term "x^2" is negative, we end up with tw0 "3x^3" that add up to "6x^3" instead of cancelling each other out.

Now, we have (3x^3-x^2). We can immediately rule out C. Moving on.

We now have (3x-1)(3x^3+x^2)=9x^4-x^2. We can rule out answer choice B because it is incomplete - we are missing the second part of the upper equation, "-6x-2." Both of the remaining answers include "-2" as the next term, whether with an x or without.

<u><em>Honestly, I haven't done algebra in a few years — while I know there's a way to deduce the rest of the equation, let's solve the equation using the two remaining answer choices and see which one is correct.</em></u>

A: (3x-1)(3x^3+x^2-2-\frac{4}{3x-1} )

=9x^4+3x^3-6x -3x^3-x^2+2-4 <u>(FOIL) (3x-1 times </u>-\frac{4}{3x-1}<u> = -4)</u>

=9x^4+3x^3-3x^3-x^2-6x+2-4  <u>(in order of exponents)</u>

=9x^4-x^2-6x+2-4 (simplify)

=9x^4-x^2-6x-2 (simplify)

<u />

D: (3x-1)(3x^3+x^2-2x-\frac{4}{3x-1} )

=9x^4+3x^3-6x^2-\frac{4}{1} -3x^3-x^2+3x+\frac{4}{1}(FOIL)

=9x^4+3x^3-3x^3-7x^2-4+4 (in order of exponents)

=9x^4-7x^2 (simplify)

A is exactly the long fraction we started with (9x^4-2-6x-x^2), just in a different order! This means that answer A, when multiplied by (3x-1), equals the same thing which, if divided by (3x-1), yields answer A. Because of the rules of multiplication/division (xy=z, z/x=y, z/y=z), this means that we have the proper set of numbers. Answer A is correct.

I hope this helps!!!!! Let me know if there's anything else I can help with :)

5 0
2 years ago
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