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MaRussiya [10]
3 years ago
7

Which of the following is a quadratic function?

Mathematics
1 answer:
rewona [7]3 years ago
4 0

the function of quadratic is number4

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The graph shows the function f(x).
Thepotemich [5.8K]

Answer:

3/2

Step-by-step explanation:

To find the rate of change

f(x2) - f(x1)

------------------ = rate of change

x2-x1

Looking at the graph

f(15) = 12

f(9) = 3

Substituting this into the equation

12-3

---------

15-9


9

------

6


3/2

The rate of change is 3/2

5 0
3 years ago
If 5(3x-1)=55 what is the value of 2x-2
cricket20 [7]

Hey ! there

Answer:

  • Value of 2x - 2 is <u>6</u><u> </u><u>.</u>

Step-by-step explanation:

In this question we are provided with an equation that is <u>5</u><u> </u><u>(</u><u> </u><u>3x</u><u> </u><u>-</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>5</u><u>5</u><u> </u>and we are asked to find the value of <u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>.</u>

Firstly , we need to find the value of x . So we need to solve the equation .

<u>SOLUTION</u><u> </u><u>:</u><u> </u><u>-</u>

\quad \longmapsto \qquad \: 5(3x - 1) = 55

<u>Step </u><u>1</u><u> </u><u>:</u> Dividing with 5 on both sides :

\quad \longmapsto \qquad \: \dfrac{ \cancel{5}(3x - 1)}{ \cancel{5}}  = \cancel{\dfrac{55}{5} }

On cancelling , We get :

\quad \longmapsto \qquad \:3x - 1 = 11

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 1 on both sides :

\quad \longmapsto \qquad \:3x -  \cancel{1} +  \cancel{1} = 11 + 1

On simplifying , We get :

\quad \longmapsto \qquad \:3x = 12

<u>Step </u><u>3 </u><u>:</u> Dividing with 3 on both sides :

\quad \longmapsto \qquad \: \dfrac{ \cancel{3}x}{ \cancel{3}}  =  \cancel{ \dfrac{12}{3} }

We get ,

\quad \longmapsto \qquad \:    \underline{\boxed{\frak{x = 4}}}

→ Therefore , value of x is <u>4</u><u> </u><u>.</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are verifying whether our answer is wrong or right . So ,

  • 5 ( 3x - 1 ) = 55

  • 5 { 3( 4 ) - 1 } = 55

  • 5 ( 12 - 1 ) = 55

  • 5 ( 11 ) = 55

  • L.H.S = R.H.S

  • Hence , Verified .

Therefore , our value of x is <u>correct</u><u>/</u><u>valid </u><u>.</u>

<u>We </u><u>need </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>.</u><u> </u>

<u>\quad \longmapsto \qquad \:2x - 2</u>

So substituting value of x in it :

<u>\quad \longmapsto \qquad \:2( \bold{4}) - 2</u>

Multiplying 2 with 4 :<u> </u>

<u>\quad \longmapsto \qquad \:8 - 2</u>

Subtracting 2 from 8 :

\quad \longmapsto \qquad \:    \blue{\underline{\boxed{\frak{6}}}}  \quad \: \bigstar

  • <u>Henceforth</u><u>,</u><u> </u><u>value </u><u>of </u><u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>is </u><u>❝</u><u> </u><u>6</u><u> </u><u>❞</u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
6 0
2 years ago
Read 2 more answers
What is the factorization of 3x2 – 8x + 5?
ELEN [110]

we have

3x^{2} -8x+5

Equate the expression to zero to find the roots

3x^{2} -8x+5=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

3x^{2} -8x=-5

Factor the leading coefficient

3(x^{2} -(8x/3))=-5

Complete the square. Remember to balance the equation by adding the same constants to each side.

3(x^{2} -(8x/3)+(16/9))=-5+(16/3)

3(x^{2} -(8x/3)+(16/9))=(1/3)

Rewrite as perfect squares

3(x-(4x/3))^{2}=(1/3)

(x-(4x/3))^{2}=(1/9)

square roots both sides

(x-\frac{4}{3})=(+/-) \sqrt{\frac{1}{9}}

x=\frac{4}{3}(+/-) \frac{1}{3}

the roots are

x=\frac{4}{3}+ \frac{1}{3}=\frac{5}{3}

x=\frac{4}{3}- \frac{1}{3}=\frac{3}{3}=1

so

3x^{2} -8x+5=3(x-\frac{5}{3})(x-1)=(3x-5)(x-1)

therefore

<u>the answer is the option</u>

(3x-5)(x-1)

6 0
3 years ago
Read 2 more answers
BRAINLIEST ASAP! PLEASE HELP ME :)
Margaret [11]

Answer:

\large \boxed{\text{3.0 mi/h}}

Step-by-step explanation:

            Let x = the current of the river

Then 21 + x  = the speed going downstream (with the current)

  a nd 21 - x  = the speed going upstream (against the current)

Distance = speed × time

           d = st

            t = d/s

Time going downstream = time going upstream

\begin{array}{rcll}\dfrac{2.4}{21+ x}& = & \dfrac{1.8}{21 - x} &\\\\2.4& = &(21 + x) \dfrac{1.8}{21 - x} &\text{Multiplied each side by (21 + x)}\\\\2.4(21 - x)& = & 1.8(21 + x) &\text{Multiplied each side by (21 - x)}\\50.4 - 2.4x&=& 37.8 + 1.8x&\text{Removed parentheses}\\50.4 & = & 37.8 + 4.2x & \text{Added 2.4x to each side}\\\end{array}\\

\begin{array}{rcll}12.6 & = & 4.2x & \text{Subtracted 37.8 from each side}\\x & = &\dfrac{12.6}{4.2}&\text{Divided each side by 4.2}\\\\ & = &\mathbf{3.0}& \text{Simplified}\\\\\end{array}\\\text{The current is $\large \boxed{\textbf{3.0 mi/h}}$}

Check:

\begin{array}{rcl}\dfrac{2.4}{21+ 3}& = & \dfrac{1.8}{21 - 3}\\\\\dfrac{2.4}{24}& = & \dfrac{1.8}{18}\\\\0.10 & = & 0.10\\\end{array}

OK

4 0
3 years ago
On commencing employment a man is paid a salary of $7200 per annum and receives annual increments of $350. Determine his salary
Marina CMI [18]

Answer:

Step-by-step explanation:

From the question, we can form an equation like: S = 7200 + 350X

where S is the salary and X is year.

1. His salary in the 9th year, means X=9, so we substitute 9 into the equation to find S = 7200 +350 (9) = 10350

2. The total he will have in the first 12years, we have:

Sum of first n terms of an <em><u>AP: S =(n/2)[2a + (n- 1)d]</u></em> where a is the value of the 1st term, here a is 7200 and d = 350 the common difference between terms

=> S = (12/2)[2*7200 + (12- 1)350] = 109500

8 0
3 years ago
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