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MaRussiya [10]
3 years ago
7

Which of the following is a quadratic function?

Mathematics
1 answer:
rewona [7]3 years ago
4 0

the function of quadratic is number4

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The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

7 0
3 years ago
WHICH SERIES OF TRANSFORMATIONS CAN BE USED TO SHOW THAT ABC~DEF?
elena-14-01-66 [18.8K]

Answer:

A) is correct

Step-by-step explanation:

7 0
2 years ago
In the first quarter of 2010, U.S. advertisers spent $5.9 billion on online
Katyanochek1 [597]

Answer:

$1.4 B per year

Step-by-step explanation:

7 0
2 years ago
There were 935 offenses in 2000 and 2448 offenses in 2019. What is the percentage increase?
Artist 52 [7]

Answer:

Approximately 262%

Step-by-step explanation:

To find the percentage increase divide the new amount of offenses by the old amount of offenses:

2448/935 = 2.618

2.618 rounds to 2.62. Convert 2.62 into a percentage: 262%

The percentage increase between the amount of offenses in 2000 and the amount of offenses in 2019 is approximately 262%.

6 0
3 years ago
A car dealership increased the price of a certain car by 13%. The original price was $47400 what is the new price?
svlad2 [7]
The answer would be 53,562. You would multiply 47400 by 1.13 to get your answer. Hope this helps!
7 0
3 years ago
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