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Contact [7]
3 years ago
9

25 points! Please help and solve step by step. Solve for x and check for extraneous solutions.

Mathematics
2 answers:
liberstina [14]3 years ago
6 0

Answer:

No real solutions

Imaginary/complex solutions:

x = 2 +/- 16sqrt(2)i

Step-by-step explanation:

(X-2)^2/3 + 13 = 5

(X-2)^2/3 = -8

(X - 2)² = (-8)³

X - 2 = +/- sqrt(-512)

No real solution

x = 2 +/- 16sqrt(2)i

(2 +/- 16sqrt(2)i - 2)^⅔ + 13 = 5

[(+/- 16sqrt(2)i)²]^⅓ + 13 = 5

(-512)^⅓ + 13 = 5

-8 + 13 = 5

5 = 5

qwelly [4]3 years ago
3 0

Answer:

no solutions

Step-by-step explanation:

(X-2)^2/3 + 13 = 5

Subtract 13 from each side

(X-2)^2/3 + 13-13 = 5-13

(x-2) ^2/3 = -8

Raise each to the 3/2 power

(x-2) ^2/3  ^3/2= -8^3/2

(x-2) = (-512) ^1/2

We cannot take the square root of a negative number and remain in the real number system

There are no solutions

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Answer:

No he didnt make the team

Step-by-step explanation:

2.86 + 3.95= 6.81

so he swam 400 meters in 6min and 81 sec but theirs 60 sec in every min so realy he swam it in 7 min and 21 sec

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4 years ago
If a ball is thrown in the air with a velocity 50 ft/s, its height in feet t seconds later is given by y = 50t - 16t2. (Round yo
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3 years ago
Determine a series of transformations that would map Figure B onto Figure C.
scZoUnD [109]

Answer:

Steps below

Step-by-step explanation:

B: (2,6) (5,9) (7,9) (8,2)

C: (-3,2) (-6,5) (-6,7) (1,8)

1. Shape B take 90° counterclockwise rotation : (x,y) ==> (-y,x)

B': (-6,2) (-9,5) (-9,7) (-2,8)

2. Shape B' horizontal translation right 3 units : (x,y) ==> (x+3,y)

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3 years ago
How can you tell if you have completely factored a polynomial?.
alexandr1967 [171]

Answer:

When no further factoring is possible or when all the factors are linear.

Step-by-step explanation:

7 0
3 years ago
Which of these is a zero of the polynomials p(y) = 3y^3 - 16 y - 8? * - 8 0 2 - 2
borishaifa [10]

The zero of polynomials is -2. The polynomials is p(y) = 3y^{3} - 16 y - 8.

According to the question,

The polynomials is p(y) = 3y^{3} - 16 y - 8. In order to find the zero of polynomials only if we substitute the value and polynomials become zero.

p(-2) = 3(-2)^{3} - 16 (-2) - 8

= 3(8) + 32 -8

= 0

Hence, the zero of polynomials is -2. The polynomials is p(y) = 3y^{3} - 16 y - 8.

Learn more about polynomials here

brainly.com/question/1720316

#SPJ4

8 0
2 years ago
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