Answer:
-1 = -5
0 = -1
2 = 5
Step-by-step explanation:
In order to do this you need to follow these five (5) steps:
1) Know what each of the variables mean in an equation of a line. The equation of a line is y = mx + b where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept. (Remember that the slope is the steepness of a line and the y-intercept is the point where the line intersects the y-axis. The x- and y-coordinates are values of the points on the line of y = 3x - 1.)
2) Identify the m (slope) and the b (y-intercept). The slope is 3, which can also be written as 3/1. The y-intercept is -1. (Remember that subtraction of 1 is the SAME thing as adding -1!) Since the y-intercept is a point it will be plotted at (0, -1).
3) Plot the y-intercept first. Start at the origin (intersection of the x- and y-axes) since the x coordinate is 0. Then move DOWN 1 unit since the y-coordinate is negative.
4) Use the m (slope) to plot at least three new points. The slope can also be represented as "rise/run" or the amount of units that you move UP or DOWN (vertically), then LEFT or RIGHT (horizontally). (Remember: if the numerator is positive (move UP); numerator is negative (move DOWN); denominator is POSITIVE (move RIGHT); denominator is NEGATIVE (move LEFT)). Since our slope is 3/1, and both the numerator and denominator are POSITIVE, that means we will be "rising" (moving UP) 3 units and "running" (moving RIGHT) 1 unit.
Start at the y-intercept of (0, -1) and move up 3 units and to the right 1 unit. You should be at (1, 2). Plot a point here. Then do it again. You should now be at (2, 5). Plot another point. Now, do it one more time. You should now be at (3, 8). Plot your last point. (If you wish to continue plotting additional points, feel free to do so.)
Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
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Answer:
-21
Step-by-step explanation:
3t-7=5t
-7=5t-3t
-7=2t
t= -7/2
6t=?
6(-7/2)= -21
Answer:
<u>Answer</u><u>:</u><u> </u><u>D</u>
• first factorise out 10:
• then find factors of the quadratic equation in the bracket:
