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Tanya [424]
4 years ago
7

If you have two drums and 4 flutes write ratio as a fraction in simplest form

Mathematics
2 answers:
SCORPION-xisa [38]4 years ago
4 0
The answer is 2:4 or 1:2
telo118 [61]4 years ago
4 0
1 drum: 2 flutes
1 drum/2 flutes
1 drum is to 2 flutes
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Convert the angle 5 radians to degrees, rounding to the nearest 10th.
lesya [120]

Step-by-step explanation:

\because {\pi}^{c}  = 180 \degree \\  \\  \therefore \:  {1}^{c}  =  \frac{180 \degree }{\pi}  \\  \\ \therefore \:  {5}^{c}  = 5 \times  \frac{180 \degree }{\pi} \\  \\ \therefore \:  {5}^{c}  = \frac{900 \degree }{\pi} \\  \\ \therefore \:  {5}^{c}  = \frac{900 \degree }{ \frac{22}{7} } \\  \\ \therefore \:  {5}^{c}  = \frac{900 \degree \times 7 }{22} \\  \\ \therefore \:  {5}^{c}  = \frac{6300}{22}  \\  \\ \therefore \:  {5}^{c}  = 286.363636\degree \\  \\  \\   \huge \red{ \boxed{\therefore \:  {5}^{c}  = 286.4\degree }}

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3 years ago
How many solutions can be found for the system of linear equations represented on the graph?
siniylev [52]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
15/5 as a mixed number
Ivanshal [37]

Answer:

the answer is 3

Step-by-step explanation:

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6 0
4 years ago
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What is the average rate of change for this exponential function for the interval from x=0 to x=2
bezimeni [28]
The equation to calculate the average rate of change is: y/x
y = f(x2) - f(x1)x = x2 - x1
x1: 1 (The smaller x value. It can be any number)x2: 2 (The larger x value. It also can be any number)f(x1): The value when you plug x1 into the function.f(x2): The value when you plug x2 into the function.
If we know this, the variables for this problem are assuming the function is 10(5.5)^x:
x2: 2x1: 1f(x2): 10(5.5)^(2) = 302.5f(x1): 10(5.5)^(1)= 55
This means:y = 302.5  - 55 = 247.5x = 2 - 1 = 1
Remember: the equation for avg rate of change is y/x
So, our average rate of change for the function on the interval [1,2] is 247.5 (y/x = 247.5/1)
8 0
3 years ago
Solve for y.<br> a.14<br> b.12<br> c.13.9<br> d.10.4
sergejj [24]

Answer:

the answer is y, I just took the test

6 0
3 years ago
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