All categories

2 years ago

Can someone help me with this question in so confused

Mathematics

1 answer:

Svetlanka [38]2 years ago

3 0

Answer:

D(1, 2) → D'(2, 7)

E(-3, -5) → E'(-10, 0)

F(4, -1) → F'(11, 4)

Step-by-step explanation:

D(1, 2) → D' ________

Translate image (3x - 1, y + 5)

(1, 2), x = 1 and y = 2

3x - 1 = 3(1) - 1 = 3 - 1 = 2

y + 5 = (2) + 5 = 7

E(-3, -5) → E' ________

(-3, -5), x = -3 and y = -5

3x - 1 = 3(-3) - 1 = -9 - 1 = -10

y + 5 = (-5) + 5 = 0

F(4, -1) → F' ________

(4, -1), x = 4 and y = -1

3x - 1 = 3(4) - 1 = 12 - 1 = 11

y + 5 = (-1) + 5 = 4

You might be interested in

Find the value of 4 + 3 x 2

aliya0001 [1]

Using PEMDAS, You know that you have to multiply first so 3*2 is 6. Than you have to add 6+4 which gives you 10... So there for 10 is your answer....

7 0

3 years ago

Read 2 more answers

Is 1 1/12 more than 1 1/3 ?

Marta_Voda [28]

No. 1/12 is a smaller amount than 1/3.

6 0

3 years ago

2.7·6.2–9.3·1.2+6.2·9.3–1.2·2.7 not pemdas

antiseptic1488 [7]

60

See steps

Step by Step Solution:

More Icon

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "2.7" was replaced by "(27/10)". 8 more similar replacement(s)

STEP

1

:

27

Simplify ——

10

Equation at the end of step

1

:

27 62 93 12 62 93 12 27

(((——•——)-(——•——))+(——•——))-(——•——)

10 10 10 10 10 10 10 10

STEP

2

:

6

Simplify —

5

Equation at the end of step

2

:

27 62 93 12 62 93 6 27

(((——•——)-(——•——))+(——•——))-(—•——)

10 10 10 10 10 10 5 10

STEP

3

:

93

Simplify ——

10

Equation at the end of step

3

:

27 62 93 12 62 93 81

(((——•——)-(——•——))+(——•——))-——

10 10 10 10 10 10 25

STEP

4

:

31

Simplify ——

5

Equation at the end of step

4

:

27 62 93 12 31 93 81

(((——•——)-(——•——))+(——•——))-——

10 10 10 10 5 10 25

STEP

5

:

6

Simplify —

5

Equation at the end of step

5

:

27 62 93 6 2883 81

(((——•——)-(——•—))+————)-——

10 10 10 5 50 25

STEP

6

:

93

Simplify ——

10

Equation at the end of step

6

:

27 62 93 6 2883 81

(((——•——)-(——•—))+————)-——

10 10 10 5 50 25

STEP

7

:

31

Simplify ——

5

Equation at the end of step

7

:

27 31 279 2883 81

(((—— • ——) - ———) + ————) - ——

10 5 25 50 25

STEP

8

:

27

Simplify ——

10

Equation at the end of step

8

:

27 31 279 2883 81

(((—— • ——) - ———) + ————) - ——

10 5 25 50 25

STEP

9

:

Calculating the Least Common Multiple

9.1 Find the Least Common Multiple

The left denominator is : 50

The right denominator is : 25

Number of times each prime factor

appears in the factorization of:

Prime

Factor Left

Denominator Right

Denominator L.C.M = Max

{Left,Right}

2 1 0 1

5 2 2 2

Product of all

Prime Factors 50 25 50

Least Common Multiple:

50

Calculating Multipliers :

9.2 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 1

Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

9.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. 837

—————————————————— = ———

L.C.M 50

R. Mult. • R. Num. 279 • 2

—————————————————— = ———————

L.C.M 50

Adding fractions that have a common denominator :

9.4 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

837 - (279 • 2) 279

——————————————— = ———

50 50

Equation at the end of step

9

:

279 2883 81

(——— + ————) - ——

50 50 25

STEP

10

:

Adding fractions which have a common denominator

10.1 Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

279 + 2883 1581

—————————— = ————

50 25

Equation at the end of step

10

:

1581 81

———— - ——

25 25

STEP

Adding fractions which have a common denominator

11.1 Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1581 - (81) 60

——————————— = ——

25 1

Final result :

7 0

3 years ago

17. Who has finished more of their homework problems? Myron or Jane?

Whitepunk [10]

7/9==0,7=7/10=70%
2/3==0,6=6/10=60%
More of their homework problems has finished Myron

5 0

2 years ago

A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape. What is th

Dmitry_Shevchenko [17]

Answer:

About 41.5%

Step-by-step explanation:

Given:

A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape.

To Find:

What is the probability that both grapes are red?

Answer choices:

about 39.7%

about 41.5%

about 42.5%

about 44.5%

Solution:

Since, there are 8 green grapes and 15 red grapes, the total number of grapes is 23 .

As the red grapes are 15..

Thus,

The probability of choosing a red grape the first time is 15/23.

Because out of the total 23 grapes only 15 were red grape.

The probability of choosing the red grape the second time will be 14/22. Because the number of red grapes has already decreased by one and so is the total number of grapes after first choice

Hence, the probability of choosing or eating two red grapes will be :

15/23×14/22

=105/253

=0.415

= 41.5%

Therefore, the probability that both grapes are red is about 41.5%

Kavinsky

4 0

2 years ago