Answer:
144 ft
Step-by-step explanation:
The object's maximum height is the same as the y-coordinate of the vertex.
To find that, first, finds the x- coordinate(t).You can find it by: first identifying a, b and c.
Multiply the b by negative 1 or simply change its sign and divide it by 2a.
Afterward, plug the answer in the equation to find y, your answer.(ax+bx²+c=-16t²+64t+80).
Therefore, a=-6, b= 64 and c=80-64/2(-16)=-64/-32=2-16(2)²+64(2)+80=144 ft
So the maximum height of the object, when launched 64ft/sec from a platform that is 80 ft high, is 144 ft
Answer: D
Step-by-step explanation: Hope this helps :)
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Answer:
X=-3, y=-4, z=-5
Step-by-step explanation:
X-4y+3z=-2......(1)
2x-y+4z=-22....(2)
3x-3y+4z=-17.....(3)
-2(1)+(2) and -3(1)+(3) we get:
7y-2z=-18....(4)
9y-5z=-11.....(5)
Now 5(4)-2(5) we get:
17y=-68 so
y=-4
Put y=-4 in (4) we have:
-28-2z=-18, then 2z=-10, so we have:
z=-5
Now put y=-4 and z=-5 in (1) we get:
x+16-15=-2, then
X=-3
