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NISA [10]
4 years ago
13

The board of directors of a corporation has agreed to allow the human resources manager to move to the next step in planning day

care service for employees' children if the manager can prove that at least 25% of the employees have interest in using the service. The HR manager polls 300 employees and 90 say they would seriously consider utilizing the service.
At the 0.10 level of significance, is there enough interest in the service to move to the next planning stage?
Mathematics
1 answer:
denis-greek [22]4 years ago
8 0

Answer:

Yes, at the 0.10 level of significance, there is enough interest in the service to move to the next planning stage.

Step-by-step explanation:

We are given that the board of directors of a corporation has agreed to allow the human resources manager to move to the next step in planning daycare service for employees' children if the manager can prove that at least 25% of the employees have interest in using the service.

The HR manager polls 300 employees and 90 say they would seriously consider utilizing the service.

<em />

<em>Let p = population proportion of employees who seriously consider utilizing the service</em>

SO, <u>Null Hypothesis,</u> H_0 : p \geq 25%   {means that the service will move to the next planning stage}

<u>Alternate Hypothesis</u>, H_a : p < 25%   {means that the service will not move to the next planning stage}

The test statistics that will be used here is <u>One-sample z proportion test statistics</u> because we don't know about the population standard deviation;

               T.S.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~  N(0,1)

where,  \hat p = sample proportion of employees who seriously consider

                   utilizing the service = \frac{90}{300} = 0.30

             n = sample of employees = 300

So, <u><em>test statistics</em></u>  =  \frac{0.30-0.25}{\sqrt{\frac{0.30(1-0.30)}{300} } }  

                               =  1.889

Now at 0.10 significance level, the z table gives critical value of -1.2816 for left-tailed test. Since our test statistics is more than the critical value of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that there is enough interest in the service to move to the next planning stage.

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A gold mine has two​ elevators, one for equipment and another for the miners. The equipment elevator descends 77 feet per second
Nuetrik [128]

Answer:

The position of the equipment elevator is 315 feet deep.

The position of the elevator of the miners is 208 feet deep.

At that time, the equipment elevator is deeper.

Step-by-step explanation:

Observation: Seems the numbers are doubled. 77 instead of 7; 1313 instead of 13; 2929 instead of 29; and 1616 instead of 16.

Hence, the question is:

A gold mine has two​ elevators, one for equipment and another for the miners. The equipment elevator descends 7 feet per second. The elevator for the miners descends 13 feet per second. One​ day, the equipment elevator begins to descend. After 29 ​seconds, the elevator for the miners begins to descend. What is the position of each elevator relative to the surface after another 16 ​seconds? At that​ time, which elevator is​ deeper?

Step-by-step explanation:

From the question,

For the equipment elevator

Speed= 7 feet/second

For the elevator of the miners,

Speed= 13 feet/second

To determine the positions of each elevator relative to the surface, we will determine the distance each of the elevator descends.

From the formula

Speed= Distance / Time

Then,

Distance = Speed × Time

From the question,

The equipment elevator begins to descend and after 29 ​seconds, the elevator for the miners begins to descend. To determine the position of each elevator after another 16 ​seconds. That is, the equipment elevator descends for a total of (29+16) seconds and the elevator of the miners descends for 16 seconds.

For the equipment elevator

Speed= 7 feet/second

Time = 29 + 16 seconds = 45 seconds

From,  Distance = Speed × Time

∴ Distance = 7 feet/second × 45 seconds

Distance = 315 feet

Hence, the position of the equipment elevator is 315 feet deep.

For the elevator of the miners

Speed = 13 feet/second

Time = 16 seconds

Distance = Speed × Time

∴ Distance = 13 feet/second × 16 seconds

Distance = 208 feet

Hence, the position of the elevator of the miners is 208 feet deep.

At that time the equipment elevator is deeper.

8 0
4 years ago
Use the four functions below for this question:
Darina [25.2K]
f (x ) = 2 x + 5
For g (x) we will solve the system:
- 1 =-2 m + b
+
-9 = 2 m + b
----------------------
-10 = 2 b,  b = -5
-9 = 2 m - 5
2 m = -4
m = -2
g ( x ) = - 2 x - 5
For h (X):
m = (-1-5 ) / ( 3-0 ) = -6/3 = -2
5 = 0 + b,   b = 5
h ( x) = - 2 x + 5.
Now we have 4 linear functions:
1 ) f ( x ) = 2 x + 5
The slope is m = 2, y - intercept: y = 5 , zero: x = -2.5 and the function increases ( m > 0 ).
2 ) g(x) = - 2 x - 5
The slope is m = - 2, y-intercept: y =-5 , zero: x = -2.5 and the function decreases ( m < 0 ).
3 ) h ( x ) = - 2 x + 5
The slope is m = - 2, y - intercept . y = 5, zero: x = 2.5 and the function decreases.
4 ) j (x) = 2 x + 5
The slope is m = 2, y -intercept: y = 5, zero: x = -2.5 and the function decreases.
The functions f( x ) and j ( x ) are parallel and also g( x ) and h ( x ). They have the same slope.  
The functions f ( x ) and j (x ) are increasing and h ( x ) and h ( x ) are decreasing.
6 0
4 years ago
What is the slope of the line that passes through (-2,-3) and (1,1)
kramer
Slope:
m =  \frac{y _{2} - y _{1}}{x_{2} - x _{1}}

Slope is rise over run. It is a ratio of the amount of the y-axis over the amount of x-axis. So, now assign the first group of numbers, (-2,-3) as 1; then the second group, (1,1) as 2. Like this:
first \: group(x _{1} ,y _{1}) \\ second \: group(x_{2},y_{2})
Notice the subscripted numbers designate the group number. Next, plug in the numbers and do the math.
\frac{1 - ( - 3)}{1 - ( - 2)}  =  \frac{1 + 3}{1 + 2}  =  \frac{4}{3}
So, the slope, m, is equal to four thirds.

m = 4/3
6 0
3 years ago
Find the 75th term of the arithmetic sequence -17, -13, -9....
Sphinxa [80]

Answer:

The 75th term of the arithmetic sequence -17, -13, -9.... is:

a_{75}=279

Step-by-step explanation:

Given the sequence

-17, -13, -9....

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

computing the differences of all the adjacent terms

-13-\left(-17\right)=4,\:\quad \:-9-\left(-13\right)=4

The difference between all the adjacent terms is the same and equal to

d=4

The first element of the sequence is:

a_1=-17

now substitute d=4 and a_1=-17 in the nth term of the sequence

a_n=a_1+\left(n-1\right)d

a_n=4\left(n-1\right)-17

a_n=4n-21

Now, substitute n = 75 in the a_n=4n-21 sequence to determine the 75th sequence

a_n=4n-21

a_{75}=4\left(75\right)-21

a_{75}=300-21

a_{75}=279

Therefore,  the 75th term of the arithmetic sequence -17, -13, -9.... is:

a_{75}=279

3 0
3 years ago
Given that y varies jointly as x and z, and y = 13 when x = 5
seraphim [82]

Step-by-step explanation:

y=kxz

13=k x 5 x 8

13= 40k

K=13/40

a. y=13/40 x 4 x 10

y=13/40 x 40

y=13

b. 20=13/40 x x x 12

20=13/40 x 12x

20=<u>156x</u>

40

20 x 40=156x

800=156x

X=<u>800</u>

156

X=<u>200</u>

39

X=5 5/39

C. 15=13/40 x 6 x z

15=<u>78z</u>

40

15x40=78z

600=78z

Z=<u>600</u>

78

Z=<u>100</u>

3

Z=7 9/13

6 0
3 years ago
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