Answer:
The position of the equipment elevator is 315 feet deep.
The position of the elevator of the miners is 208 feet deep.
At that time, the equipment elevator is deeper.
Step-by-step explanation:
Observation: Seems the numbers are doubled. 77 instead of 7; 1313 instead of 13; 2929 instead of 29; and 1616 instead of 16.
Hence, the question is:
A gold mine has two elevators, one for equipment and another for the miners. The equipment elevator descends 7 feet per second. The elevator for the miners descends 13 feet per second. One day, the equipment elevator begins to descend. After 29 seconds, the elevator for the miners begins to descend. What is the position of each elevator relative to the surface after another 16 seconds? At that time, which elevator is deeper?
Step-by-step explanation:
From the question,
For the equipment elevator
Speed= 7 feet/second
For the elevator of the miners,
Speed= 13 feet/second
To determine the positions of each elevator relative to the surface, we will determine the distance each of the elevator descends.
From the formula
Speed= Distance / Time
Then,
Distance = Speed × Time
From the question,
The equipment elevator begins to descend and after 29 seconds, the elevator for the miners begins to descend. To determine the position of each elevator after another 16 seconds. That is, the equipment elevator descends for a total of (29+16) seconds and the elevator of the miners descends for 16 seconds.
For the equipment elevator
Speed= 7 feet/second
Time = 29 + 16 seconds = 45 seconds
From, Distance = Speed × Time
∴ Distance = 7 feet/second × 45 seconds
Distance = 315 feet
Hence, the position of the equipment elevator is 315 feet deep.
For the elevator of the miners
Speed = 13 feet/second
Time = 16 seconds
Distance = Speed × Time
∴ Distance = 13 feet/second × 16 seconds
Distance = 208 feet
Hence, the position of the elevator of the miners is 208 feet deep.
At that time the equipment elevator is deeper.
