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3 years ago

Find the area of a circle with a diameter of 1.5 m. 4.71 m2 1.77 m2

Mathematics

1 answer:

nikdorinn [45]3 years ago

7 0

I hope this helps you

radius=diameter/2

radius=1,5/2

radius=0,75

Area=pi. r^2

Area=3,14. (0,75)^2

Area=1,76

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The answer is 40.74kg because you divide my 100, multiply by three ad subtract from 42!

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3 years ago

Read 2 more answers

Can someone please help me solve this system of equations

sergejj [24]

Answer:

x=15 and y=2

Step-by-step explanation:

The given system of equations is

8y - x = 1 ...............(i)

and

10 y = x + 5 ...............(ii)

Now from equation (ii)

10 y = x + 5

subtracting -5 from both sides

10 y - 5 = x + 5 - 5

10 y -5 = x

x = 10y -5 ............(iii)

Put this in equation (i)

it becomes

8y - (10y -5) = 1

8y-10y+5=1

-2y+5 =1

subtracting 5 from both sides

-2y + 5 -5 = 1 -5

-2y = -4

dividing both sides by -2 gives

-2y / -2 = -4 / -2

y = 2

We got the value of y putting it in equation (iii) to get the value of x

as from equation (iii)

x = 10y-5

x = 10(2) - 5

x = 20 -5

x = 15

So this is the solution from the equations

4 0

3 years ago

Help guys make p da subject of the formula

Basile [38]

Answer:

$p=\dfrac{m}{k-s}$

Step-by-step explanation:

When they ask you to make a variable the "subject of the formula", they're basically asking you to build a "machine" for it. In the expression $y=mx+b$ , for instance, if we know what m, x, and b are, we can plug them all in and out comes a value for y! To build that machine, we need to get it by itself on one side of the equation.

So, we want to build this machine for p, and the equation we have to build it out of is

$1=\dfrac{pk}{m+sp}$

One think we can immediately say about this equation: for a fraction to be equal to one, its numerator and denominator have to be equal to each other. So we can say

$m+sp=pk$

Ok, what next? Well, if we want p by itself, we need to somehow peel it off of that sp and pk. Let's collect them on the right side by subtracting sp from both sides:

$m=pk-sp$

p is a common factor of both sp and pk, so we can peel it away using the distributive property:

$m=p(k-s)$

And from here, we can divide both sides by $k-s$ and we'll have p as our subject:

$\dfrac{m}{k-s}=p$ or $p=\dfrac{m}{k-s}$

So if we know m, k, and s, we can easily solve for p. If m = 4, k = 2, and s = 0:

$p=\frac{4}{2-0} =\frac{4}{2}=2$

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3 years ago

What is 6f-23=[-5] plz help

xz_007 [3.2K]

Add 23 from both sides
6f = 18
F= 3

6(3)-23
= 18-23
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Believe me

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3 years ago

Which of the following statements about the sampling distribution of the sample mean, x-bar, is not true? A. The sampling distri

Elenna [48]

Answer: E. All of the above statements are true

Step-by-step explanation:

The mean of sampling distribution of the mean is simply the population mean from which scores were being sampled. This implies that when population has a mean μ, it follows that mean of sampling distribution of mean will also be μ.

It should also be noted that the distribution's shape is symmetric and normal and there are no outliers from its overall pattern.

The statements about the sampling distribution of the sample mean, x-bar that are true include:

• The sampling distribution is normal regardless of the shape of the population distribution, as long as the sample size, n, is large enough.

• The sampling distribution is normal regardless of the sample size, as long as the population distribution is normal. • The sampling distribution's mean is the same as the population mean.

• The sampling distribution's standard deviation is smaller than the population standard deviation.

Therefore, option E is the correct answer as all the options are true.

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3 years ago