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3 years ago

Classify the angle as acute, right, obtuse, or straight.

Mathematics

1 answer:

taurus [48]3 years ago

5 0

Answer:

Step-by-step explanation:

Our eyes tell us that the angle is less than 90 degrees. That's the definition of Acute.

A right angle = 90 degrees.

An obtuse angle is larger than 90 degrees.

A straight angle is a line which = 180 degrees.

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Find the measure of indicated unknown angle

RSB [31]

Answer:

Step-by-step explanation:

90÷2=45

45+75+m=180(sum of triangle)

120+m =180

m=180-120

m=60

4 0

3 years ago

WORTH ALOT. Find the amount that results from the investment. 14) $480 invested at 7% compounded quarterly after a period of 9 y

konstantin123 [22]

Answer:

$896.36

Step-by-step explanation:

Principal = $480
Interest rate = 7% compounded
Compound number = 4 per year
Time = 9 years

<u>Final amount is:</u>

480*(1 + 0.07/4)^(9*4) =
480(1.0175)^36 =
$896.36

4 0

3 years ago

Read 2 more answers

Lilly bought a $35 teddy bear and she only had $25 how can she make more money without a job? (she is a child)

RoseWind [281]

Answer: She can sell lemonade, she can dog sit with her mom/sister/dad or brother or whoever, She can make things and sell them, She can have a garage sell with her family. (Just some few ways) :3

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4 years ago

Myles's school is selling tickets to an end of the year

dusya [7]

Answer:

about 13$ and 6 cents

Step-by-step explanation:

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3 years ago

A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like

mixas84 [53]

Answer:

a) $\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) $\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) the steady state mass of the drug is 2000 mg

d) t ≅ 153.51 minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

$Rate _{(in)}= 500 \ mg/L \times 0.06 \ L/min = 30 mg/min$

$Rate _{(out)}=\dfrac{x}{4} \ mg/L \times 0.06 \ L/min = 0.015x \ mg/min$

Therefore;

$\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}$

with respect to x(0) = 0

$\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

$\dfrac{dx}{dt} = -0.015(x - 2000)$

$\dfrac{dx}{(x - 2000)} = -0.015 \times dt$

By Using Integration Method:

$ln(x - 2000) = -0.015t + C$

$x -2000 = Ce^{(-0.015t)$

$x = 2000 + Ce^{(-0.015t)}$

However; if x(0) = 0 ;

Then

C = -2000

Therefore

$\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

$\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}$

x = 2000 - 0

x = 2000

Thus; the steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

$\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}$

$0.1 = e^{(-0.015t)$

$ln(0.1) = -0.015t$

$t = -\dfrac{In(0.1)}{0.015}$

t = 153.5056729

t ≅ 153.51 minutes

4 0

3 years ago