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mrs_skeptik [129]
2 years ago
6

Multiply. State any excluded values. q+5/-3 * -3q/q+2

Mathematics
1 answer:
lyudmila [28]2 years ago
4 0
The given equation is:

\frac{q+5}{-3} * \frac{-3q}{q+2}

Just multiply both numerators and both denominators respectively, with the bar line still between them. So, it becomes

\frac{(q+5)(-3q)}{(-3)(q+2)} = \frac{-3 q^{2}-15q }{-3q-6} 


Then you factor out the equations:

\frac{-3 q^{2}-15q }{-3q-6} = \frac{-3q(q+5)}{-3(q+2)} 


Simplify terms by dividing them. The negative sign and 3 cancels out. The answer would be:

\frac{q(q+5)}{(q+2)}

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