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yanalaym [24]
3 years ago
14

Find the area of the triangle.

Mathematics
1 answer:
pentagon [3]3 years ago
5 0
The correct anwser is 12
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17) Find the surface area of the right triangular prism shown below:<br> 5<br> 2<br> 5/2<br> 3/2
harkovskaia [24]

Answer:

D

Step-by-step explanation:

They didn't provide the number for one of the faces btw..

7 0
3 years ago
what is the slope of a line parallel to the line whose equation is y= -5/2x+7. fully simplify your answer
Feliz [49]

Answer:

-5/2

Step-by-step explanation:

7=intersect of y

-5/2=Slope

7 0
3 years ago
Anika is hiking on a rectangular trail at the national park. There are four resting spots along the corners of the trail. On the
tia_tia [17]
The perimeter is 10 try to draw these points on the graph and count the distance between each or you can just look at the coordinates and find the distance and then add length and width
4 0
3 years ago
The price P of a good and the quality Q of a good are linked.
Irina-Kira [14]

the equilibrium point, is when Demand = Supply, namely, when the amount of "Q"uantity demanded by customers is the same as the Quantity supplied by vendors.

That occurs when both of these equations are equal to each other.

let's do away with the denominators, by multiplying both sides by the LCD of all fractions, in this case, 12.


\bf \stackrel{\textit{Supply}}{-\cfrac{3}{4}Q+35}~~=~~\stackrel{\textit{Demand}}{\cfrac{2}{3}Q+1}\implies \stackrel{\textit{multiplying by 12}}{12\left( -\cfrac{3}{4}Q+35 \right)=12\left( \cfrac{2}{3}Q+1 \right)} \\\\\\ -9Q+420=8Q+12\implies 408=17Q\implies \cfrac{408}{17}=Q\implies \boxed{24=Q} \\\\\\ \stackrel{\textit{using the found Q in the Demand equation}}{P=\cfrac{2}{3}(24)+1}\implies P=16+1\implies \boxed{P=17} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{Equilibrium}{(24,17)}~\hfill



3 0
3 years ago
I need help on this question plz
drek231 [11]

Given is triangle with base = 10 cm and perpendicular height = 3 cm.

We know the formula for area of triangle is given by :-

Area = \frac{1}{2} × (Base) × (perpendicular height)

Area = \frac{1}{2} × (10) × (3)

Area = \frac{30}{2}

Area = 15 cm²

So, final answer is 15 cm².

3 0
3 years ago
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