1. First, let us define the width of the rectangle as w and the length as l.
2. Now, given that the length of the rectangle is 6 in. more than the width, we can write this out as:
l = w + 6
3. The formula for the perimeter of a rectangle is P = 2w + 2l. We know that the perimeter of the rectangle in the problem is 24 in. so we can rewrite this as:
24 = 2w + 2l
4. Given that we know that l = w + 6, we can substitute this into the formula for the perimeter above so that we will have only one variable to solve for. Thus:
24 = 2w + 2l
if l = w + 6, then: 24 = 2w + 2(w + 6)
24 = 2w + 2w + 12 (Expand 2(w + 6) )
24 = 4w + 12
12 = 4w (Subtract 12 from each side)
w = 12/4 (Divide each side by 4)
w = 3 in.
5. Now that we know that the width is 3 in., we can substitute this into our formula for length that we found in 2. :
l = w + 6
l = 3 + 6
l = 9 in.
6. Therefor the rectangle has a width of 3 in. and a length of 9 in.
Answer:
Step-by-step explanation:
Here you go mate
Step 1
7+(42-5)-0 Equation/Question
Step 2
7+(42-5)-0 Simplify
7+37+(-0)
44+(-0)
44+0
Step 3
44+0 Add them
answer
44
Hope this helps
The right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.
Let be an <em>exponential</em> function of the form
, where
and
are <em>real</em> numbers. A <em>horizontal</em> asymptote exists when
, which occurs for
.
For this function, the <em>horizontal</em> asymptote is represented by
and to change the value of the asymptote we must add the <em>parent</em> function by another <em>real</em> number (
), that is to say:
(1)
In this case, we must use
to obtain an horizontal asymptote of -3. Thus, the right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.
To learn more on asymptotes, we kindly invite to check this verified question: brainly.com/question/8493280