3x - 3y + 9 = 0
The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b). It is also the value of y when x = 0.
To solve for the y-intercept, set x = 0:
3(0) - 3y + 9 = 0
3(0) - 3y + 9 = 0
Subtract 9 from both sides:
- 3y + 9 - 9 = 0 - 9
- 3y = -9
Divide both sides by -3 to solve for y:
-3y/-3 = -9/-3
y = 3
Therefore, the y-intercept is (0, 3).
The x-intercept is the point on the graph where it crosses the x-axis, and has coordinates of (a, 0). It is also the value of x when y = 0.
To solve for the x-intercept, set y = 0:
3x - 3(0)+ 9 = 0
3x -0 + 9 = 0
Subtract 9 from both sides:
3x + 9 - 9 = 0 - 9
3x = -9
Divide both sides by 3 to solve for x:
3x/3 = -9/3
x = -3
Therefore, the x-intercept is (-3,0).
The correct answers are:
Y-intercept = (0, 3)
X-intercept = (-3, 0)
Answer:
Construction of an angle bisector is partially represented by the diagram on the baseball field.
Step-by-step explanation:
Angle bisector of an angle bisects it into two equal angles.
Construction of an angle bisector is partially represented by the diagram on the baseball field.
Consider the figure:
From point B, draw an arc by opening the compass up to the same extend as we did while drawing arc from point A.
Take the point of intersection of both the arcs as C.
Join OC.
OC is the angle bisector of the angle.
Given:
Rate of reduction : 85%
Remaining volume: 120 ml.
This means that 120 ml is equivalent to 15% of the original volume.
100% - 85% = 15%
120 ml ÷ 15% = 800 ml.
There was 800 ml of water before it was reduced.
800 ml * 85% = 680 ml ⇒ volume reduced
800 ml - 680 ml = 120 ml ⇒ volume left after reduction.
Answer:first one A second one D third A
please give me brianlest and I will answer every question you put
Answer:
Step-by-step explanation:
<u>Trigonometric Formulas</u>
To solve this problem, we must recall some basic relations and concepts.
The main trigonometric identity relates the sine to the cosine:
The tangent can be found by
The cosine and the secant are related by
They both have the same sign.
The sine is positive in the first and second quadrants, the cosine is positive in the first and fourth quadrants.
The sine is negative in the third and fourth quadrants, the cosine is negative in the second and third quadrants.
We are given
Find the cosine by solving
We have placed the negative sign because we know the secant ('sex') is negative and they both have the same sign.
Now compute the tangent
Rationalizing