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Shtirlitz [24]
3 years ago
13

A circle has a circumference of 16π. What is the radius of the circle?

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
7 0
Radius = Circumference / 2π
r = 16π/2π
r = 8

In short, Your Answer would be 8

Hope this helps!
VashaNatasha [74]3 years ago
5 0

Answer:

8 units.

Step-by-step explanation:

As the given data is the circumference, we are going to use the circumference formula to find the radius.

C=2\pi r

where C is the circumference and r is the radius, then

16\pi=2\pi r

\frac{16\pi}{2\pi} = r

8 = r

Then, the radius of the circle is 8 units.

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1+1+1+1 what is the correct answer ​
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1+1+1+1

First, let's do 1+1

1+1=2

and the other 1+1 also equals 2

2+2=4

so the final answer is 4

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Answer:

C. 500 ft

Step-by-step explanation:

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2000 ÷ 4 = 500

He should travel <u>500 feet</u> in each descent.

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Vector u has its initial point at (-7, 2) and its terminal point at (11, -5). Vector v has a direction opposite that of vector u
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7 0
3 years ago
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Please help me out thank you!!
Verdich [7]

g(2) means plug in x = 2 into the function g(x) = |-2x + 4| and f(-1) means plug x = -1 into f(x) = 3x - 1.

That will give you two numbers that you can then use to calculate g(2) - f(-1)

5 0
2 years ago
Read 2 more answers
Suppose that when a transistor of a certain type is subjected to an accelerated life test, the lifetime x (in weeks) has a gamma
elena-14-01-66 [18.8K]

Answer:

a) P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

b) P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

Step-by-step explanation:

Previous concepts

The Gamma distribution "is a continuous, positive-only, unimodal distribution that encodes the time required for \alpha events to occur in a Poisson process with mean arrival time of \beta"

Solution to the problem

Let X the random variable that represent the lifetime for transistors

For this case we have the mean and the variance given. And we have defined the mean and variance like this:

\mu = 40 = \alpha \beta  (1)

\sigma^2 =320= \alpha \beta^2  (2)

From this we can solve \alpha and [/tex]\beta[/tex]

From the condition (1) we can solve for \alpha and we got:

\alpha= \frac{40}{\beta}    (3)

And if we replace condition (3) into (2) we got:

320= \frac{40}{\beta} \beta^2 = 40 \beta

And solving for \beta = 8

And now we can use condition (3) to find \alpha

\alpha=\frac{40}{8}=5

So then we have the parameters for the Gamma distribution. On this case X \sim Gamma (\alpha= 5, \beta=8)

Part a

For this case we want this probability:

P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

Part b

For this case we want this probability:

P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

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3 years ago
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