Answer:
Equation of line in slope-intercept form that passes through (4, -8) and is perpendicular to the graph
is below

Step-by-step explanation:
Slope of the equation
is 
Since slopes of perpendicular lines are negative reciprocal of each other, therefore slope of other line is given as

Equation of line in point slope form is given as

Here (x1, y1) = (4, -8)

Simplifying it further


First, convert "of" to x and put this info into an equation:
Let n represent the unknown number.
14.4 % x n= 10.4
n = 10.4 / 14.4%
n = 72.22222
n = ~72
Hope this helps!
It is a false statement that the <span>bisector of a straight angle forms two acute angles. The correct option among the two options that are given in the question is the second option or the last option. I hope that this is the answer that you were looking for and and it has actually come to your desired help.</span>
Answer:
x = 400 when y = 100
Step-by-step explanation:
This is a question in relation to direct variation.
y ∝ 
y = k 
Given that, y = 45, x = 81. Then;
45 = k 
45 = 9k
k = 
k = 5
Thus the relationship among the variables is;
y = 5 
If y = 100, then;
100 = 5 
= 
= 20
x = 
x = 400
Therefore, x = 400 when y = 100.