Answer:
help with what
Step-by-step explanation:
Its 8:00, because four 15 minutes is 9:00, so when you go back four 15 minutes, its 8:00
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
robux
Step-by-step explanation:
1p robux ca rjs djsj
<span>the tens digit = n
</span><span>the units digit = n-5
n + n-5 = 9
2n = 9+5
2n = 14
n = 7 </span>← the tens digit
the units digit = n-5 = 7 - 5 = 2
<span>the number is 72</span>
