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Ray Of Light [21]
3 years ago
8

Given an int variable k that has already been declared, use a while loop to print a single line consisting of 88 asterisks. Use

no variables other than k.
k=1;
while(k<=88) {
System.out.print('*');
k++;
}
System.out.println(); T/F
Computers and Technology
1 answer:
Grace [21]3 years ago
6 0

Answer:

True

Explanation:

The while loop is going to be executed until the condition is false.

Since <em>k</em> is initially equal to 1, the loop will execute 88 times. One asterisk will be printed and <em>k</em> will be incremented by one during each iteration.

When <em>k</em> becomes 89, the condition will be false (89 is not smaller or equal to 88) and the loop will stop.

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Write a C program that has the following statements: int a, b; a = 10; b = a + fun(); printf("With the function call on the righ
mart [117]

Answer:Following is the C program:-

#include <stdio.h>

int fun()//function fun of return type int and it returns value 6.

{

   return 6;

}

int main() {

  int a, b;

  a = 10;

  b = a + fun();//adds 6 to a.

  printf("With the function call on the right, ");

  printf("\n%d ",b);//printing b..

return 0;

}

Output:-

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16

Explanation:

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Answer:

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Explanation:

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