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likoan [24]
3 years ago
13

Damage to which portion of the limbic system results in loss of memory of recent events and difficulty committing anything new t

o memory?
Computers and Technology
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

Hippocampus.

Explanation:

There are two parts of the limbic system. They are the frontal part which is the amygdala and the posterior part which is the hippocampus.

The hippocampus is an extension of the temporal part  of the cerebral cortex which is a plastic-like structure that can be easily damaged by stimuli. It is packed with densed neurons and forms an S-shape at the extension of the temporal part.

It is responsible for learning and memory and damage to it can result to memory loss of recently learnt information.

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Four categories of installer apps
Naddika [18.5K]

Answer:

I find 5 categories

Explanation:

1 Overview

2 Necessity

3 Types

4 Attended installation

4.1 Silent installation

4.2 Unattended installation

4.3 Headless installation

4.4 Scheduled or automated installation

4.5 Clean installation

4.6 Network installation

5 Installer

5.1 Bootstrapper

5.2 Common types

5.3 System installer

7 0
3 years ago
Windows needs free space on the hard drive for normal operation, for defragmenting the drive, for burning CDs and DVDs, and for
REY [17]

Answer:

True

Explanation:

Windows writes temporary files to the hard disk which it uses as a cache during normal operation. These files are usually deleted automatically after the windows operation has been completed. If there is no free disk space available, some windows operations will fail to start and others will stop working

3 0
3 years ago
In ______ each station is assigned a code; using a special coding scheme, stations send data over the entire bandwidth of the ch
Viktor [21]

Answer:

CDMA is sa station.

Explanation:

CDMA is basically a Code Division Multiple Access .It is assgned code that facilitates the signals or special coding scheme.It optimizes the use of bandwidth, It is used in a UHF and send data over entire bandwidth of channel.It send data without sharing of capacity of channel. Its ranges is between 800 MHz and 1.9 GHz

4 0
3 years ago
A large gambling company needs to be able to accept high volumes of customer wagers within short timeframes for high-profile spo
Dima020 [189]

Answer: A. a mobile app that only accepts wagers based on the user's location

Explanation:

Elastic cloud simply refers to the cloud computing offering which due to the need for change helps in the provision of variable service levels.

Based on the information given in the question, an effective elastic Cloud solution that can meet this client’s needs is a mobile app that only accepts wagers based on the user's location.

Since there are strict laws that prohibit gambling activities outside the licensed zones, the user location is vital in the mobile app.

5 0
3 years ago
write a program, using python, to determine the mean, median, and standard deviation of a list of numbers. In addition, count th
Mekhanik [1.2K]

Answer:

The program to this question can be given as:

Program:

import math   #import packages

import sys

number =  [3, 6, 7, 2, 8, 9, 2, 3, 7, 4, 5, 9, 2, 1, 6, 9, 6]  #define list  

n = len(number)   # taking length of list

print("Sample Data: ",number)  #print list

#find Mean

print("Mean is: ")  #message  

add = sum(number)  # addition of numbers.

mean = add / n  #add divide by total list number.

print(str(mean))  #print mean

number.sort()   #short list by using sort function

#find Median

print("Median is: ")

if n % 2 == 0:        #conditional statement.

   median1 = number[n//2]  

   median2 = number[n//2 - 1]  

   median = (median1 + median2)/2

else:  

   median = number[n//2]  

print(str(median)) #print median

#find Standard deviation.

print("Standard Deviation :")

def SD(number):  #define function SD

   if n <= 1:      #check condition

       return 0.0   #return value.

   mean,SD = average(number), 0.0  

   # find Standard deviation(SD).

   for j in number:

       SD =SD+(float(j)-mean)**2

       #calculate Standard deviation holing in variable SD  

       SD =math.sqrt((SD)/float(n-1))#using math sqrt function.

   return SD  #return value.

def average(av):         #define function average

   n,mean =len(av), 0.0  

   if n <= 1:

       return av[0]   #return value.

   # calculate average

   for I in av:

       mean +=float(i)

       mean /= float(n)

   return mean             #return value.

print(SD(number)) #print value

Output:

Sample Data:  [3, 6, 7, 2, 8, 9, 2, 3, 7, 4, 5, 9, 2, 1, 6, 9, 6]

Mean is:  

5.235294117647059

Median is:  

6

Standard Deviation :

2.140859045465338

Explanation:

In the above python program first, we import packages to perform maths and other functions. Then we declare the list that is number in the list the elements are given in the question. Then we declare variable n in this variable we take the number of elements present in the list and print the list first. In the list, we perform three operations that can be given as:

Mean:  

In the mean operation firstly we define the variable add in this variable we add all elements of the list by using the math sum function then we divide the number by number of elements present in the list. and sore the value in the mean variable and print it.

Median:

In the median section firstly we sort the list by using the sort function. Then we use the conditional statements for calculating median. In the if block first we modules the number by 2 if it gives 0. it calculates first and second median the add-in median .else it will print that number.

Standard Deviation:

In the standard deviation part first, we define two functions that is SD() function and average().In the SD() function we pass the list as the parameter. In this function we use the conditional statement in the if block we call the average() function and use for loop for return all values. In the average() function we calculate the average of the all number and return value. At last, we print all values.

7 0
3 years ago
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