D(-2,5)
C(-2,-3)
E(8,5)
F(8,-3)
A(2,5)
B(8,1)
C(-2,-3)
AD= 4 units
DC= 8 units
AE = 6 units
EB = 4 units
BF = 4 units
CF = 10 units
ADC = 16 sq units
AEB = 12 sq units
BFC = 20 sq units
90 -16 -12 -20 = 42 sq units
Hope this is the right answer ☺
<span>Cold fronts are marked on weather maps with the symbol of a blue line of triangles/spikes (pips) pointing in the direction of travel, and are placed at the leading edge of the cooler air mass. That cold/dense air wedges its way under the warm air out ahead of it.
</span><span>Warm fronts are marked on weather maps with a red line of half circles pointing in the direction of travel and mark the edge of an advancing warm air mass; a flow of warmer air that overtakes and replaces colder air. They are usually found on the east side of low-pressure storm systems. Since the cold air is denser than the warm air, the cold air hugs the ground. The lighter warm air slides up and over the cold air (called “overrunning”) and lacks any direct push on the cold air. Thus, the cold air is slow to retreat in the rapid advance of the warm air. This slowness of the cold air to retreat produces an atmospheric slope that is more gradual than the sharper slope that accompanies a cold front.
</span><span>Stationary fronts are depicted by alternating red half-circles and blue spikes (pips) pointing in opposite directions, indicating no significant movement. When neither air mass is replacing the other, the frontal boundary becomes more-or-less stationary; the opposing forces exerted by adjacent air masses of different densities are such that the frontal surface between them shows little or no movement (sometimes also referred to as a “quasi-stationary” front). In such cases, the surface winds tend to blow parallel to the frontal zone. The resultant weather is usually low cloud cover and long duration precipitation, and not much in the way of wind.
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i gave yu a little bit more info but read the stationary one
<span>A. line
Planes intersect in a line when they meet each other.</span>
To find the percentage, take the part (111) over the whole (300) then multiply the quotient by 100.
111 / 300 = 0.37
0.37 × 100 = 37%
Sorry I don't know but u could find the answer on Google
