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VARVARA [1.3K]
3 years ago
11

What is the product of (3+radical 5) and (3-radical 5)

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
5 0
(3 + √((5)) + (3 - √(5))
3(3 - √(5)) + √(5)(3 - √(5)))
3(3) - 3(√(5)) + √(5)(3) + √(5)(√(5))
9 - 3√(5) + 3√(5) - √(25)
9 - 5
4
schepotkina [342]3 years ago
4 0
(3 + \sqrt{5}) × (3 - \sqrt{5})
Take the special case
(a - b)×(a + b)=a² - b²

a = 3
b = \sqrt{5}

3² - (\sqrt{5})²     {(√)² = the number itself}
              9 - 5
                4 
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Given: triangle LNK, m of angle NLK =72 degrees. m of angle N=58 degrees. MP is perpendicular bisector of side LK and intersects
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Answer:

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Step-by-step explanation:

<u>Given triangle LNK </u>

  • m∠NLK = 72°
  • m∠LNK = 58°
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<u>Interior angles sum to 180°</u>

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  • 72° + 58° + m∠LKN = 180°
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Step-by-step explanation:

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