Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me
Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me Help me
2 answers:
You might be interested in
Answer:
m∠CFD is 70°
Step-by-step explanation:
In the rhombus
- Diagonals bisect the vertex angles
- Every two adjacent angles are supplementary (their sum 180°)
Let us solve the question
∵ CDEF is a rhombus
∵ ∠E and ∠F are adjacent angles
→ By using the second property above
∴ ∠E and ∠F are supplementary
∵ The sum of the measures of the supplementary angles is 180°
∴ m∠E + m∠F = 180°
∵ m∠E = 40°
∴ 40° + m∠F = 180°
→ Subtract 40 from both sides
∵ 40 - 40 + m∠F = 180 - 40
∴ m∠F = 140°
∵ FD is a diagonal of the rhombus
→ By using the first property above
∴ FD bisects ∠F
→ That means FD divides ∠F into 2 equal angles
∴ m∠CFD = m∠EFD = m∠F
∴ m∠CFD = (140°)
∴ m∠CFD = 70°