Janet wanted to determine her average phone call length over 90 days. She collected the phone bills and randomly picked ten entr
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The sum will be:
sigma(i = 1 to infinity, 30*(2/5)^i)
->
Which is equal to 30/(3/5) = 50
sigma(i = 1 to infinity, 30*(2/5)^i)
->
Which is equal to 30/(3/5) = 50