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s344n2d4d5 [400]

3 years ago

13

Janet wanted to determine her average phone call length over 90 days. She collected the phone bills and randomly picked ten entr

ies to look at. The phone call lengths, in minutes, are shown below. 3, 5, 16, 5, 11, 3, 11, 3, 16, 3

1 answer:

muminat3 years ago

3 0

oops sorry wrong question. sorry if I confused anyone :(

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An item is regularly priced at $65. Laura bought it at a discount of 15% off the regular price. How much did Laura pay?

Sonja [21]

Answer:

9.75

Step-by-step explanation:

7 0

3 years ago

The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc

BaLLatris [955]

Answer:

$y(t)= 6-3cos(\dfrac{2\pi}{14}t )$

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

$y(t) = y_0+Acos(wt)$

The tide varies between 3ft and 9ft, which means its amplitude $A$ is

$A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}$

and its midline $y_0$ is

$y_o=3+3 \\\\\boxed{y_o= 6ft}$ .

Furthermore, since at $t=0$ the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is $-cos(\omega t)$ .

The period of the full cycle is 14 hours, which means

$\omega t =2\pi$

$\omega (t+14)= 4\pi$

giving us

$\boxed{\omega = \dfrac{2\pi}{14}.}$

With all of the values of the variables in place, the function modeling the situation now becomes

$\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}$

8 0

3 years ago

Maria received 5/7 of the 42 votes cast for class president. how many votes did she receive?

baherus [9]

42/7= 6
5*6=30
30 votes

6 0

3 years ago

Mr. Sen wants to treat a group of friends either to the movies or to a hockey game for his birthday. Both the theater and the ho

monitta

Answer:

there's no numbers to answer this question

Step-by-step explanation:

I apologize but all the information and table is gone there is no way to answer this for you

8 0

2 years ago

Help please!!!!!!!!!!!

kvasek [131]

Answer:

B. 2/3

Step-by-step explanation:

To solve this we have to take into account this axioms:

- The total probability is always equal to 1.

- The probability of a randomly selected point being inside the circle is equal to one minus the probability of being outside the circle.

Then, if the probabilities are proportional to the area, we have 1/3 probability of selecting a point inside a circle and (1-1/3)=2/3 probability of selecting a point that is outside the circle.

Then, the probabilty that a random selected point inside the square (the total probability space) and outside the circle is 2/3.

3 0

3 years ago