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klasskru [66]
3 years ago
13

Sophia exchanged 1000 U.S. dollars for the South African currency which is called the rand. The exchange rate was 8.05 rand to 1

dollar please explain how you know
Mathematics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

Sophia gets 7,150

Step-by-step explanation:

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Need help on this! (plz help)​
Lynna [10]

Step-by-step explanation:

you just need to put each in the calculator. I'm not so sure what an ALEKS calculator is

5 0
3 years ago
Mlin
antiseptic1488 [7]

Answer:

y-5 = 3/2(x-3)

Step-by-step explanation:

The point slope form of the equation of a line is

y-y1 = m(x-x1)  where m is the slope and (x1,y1) is a point on the line

y-5 = 3/2(x-3)

7 0
3 years ago
A field researcher is gathering data on the trunk diameters of mature pine and spruce trees in a certain area. The following are
lidiya [134]

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

H_0: \mu_1 - \mu_2 = 0

H_a: \mu_1 - \mu_2 > 0

In which \mu_1 is the mean pine trees height while \mu_2 is the mean spruce trees height.

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

Mean trunk diameter (cm) 35 30:

Pine trees - 35

Spruce trees - 30

The sample mean is given by the subtraction of the means. So

X = 35 - 30 = 5

Sample Size 40 80

Population variance 160 160

This means that the standard error for each sample is given by:

s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2

s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}

The standard error of the difference is the square root of the sum squared of the standard error of each sample.

s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495

Test statistic:

z = \frac{X - \mu}{s}

z = \frac{5 - 0}{2.4495}

z = 2.04

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

1 - 0.9793 = 0.0207

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

8 0
3 years ago
1/2(6+3p)-3/4(8-10p)<br> Expand and simplify
andreev551 [17]
When you take this problem and simplify it you get 9p-3
5 0
3 years ago
Read 2 more answers
Restaurant is making hamburgers. The cooks use
likoan [24]

Answer:

70.69

Step-by-step explanation:

46 2/3 divided by 2/3

46.66 divided by 0.66

The anwser is 70.69

If the cook makes twice as much beef then the number of hamburgers would be two times larger which would be 141.39.

Half as much beef would be 70.69 divided by two which is 35.34.

5 0
3 years ago
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